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How can I replace a factor levels with the top n levels (by some metric), plus [other]?

For a factor with more than a sensible number of levels to color in a graph, I want to replace any levels that are not in the 'top 10' with 'other'.

Alternate Question: How do I reduce my factor levels to the number rcolorbrewer can plot as separate colors?

For example, if I want to plot number of homeruns per decade from the baseball data:

require(ggplot2)
qplot(data=baseball,10*year%/%10,hr,
  stat="identity",geom="bar")

simple graph to set the scene

Perhaps I'd like to see what teams contributed to this:

qplot(data=baseball,10*year%/%10,hr,
  fill=team,
  stat="identity",geom="bar")

too many teams to tell colors apart or plot on page

This creates too many color levels! The colors are so similar you can't distinguish them, and there are so many they won't fit on the screen.

I'd really like to see the top X (7) teams (by total homerun count) and then the rest all lumped together in a single category/color called 'other'.

Let's imagine we have a function called hotfactor which knows how to do this:

hotfactor(afactor,orderby,count)={ ??? }

qplot(data=baseball,10*year%/%10,hr,
  fill=hotfactor(factor(team),hr,n=7),
  stat="identity",geom="bar") + 
  scale_fill_brewer("team","Dark2")

sample image for solution

So what can I use for 'hotfactor'?

like image 705
Alex Brown Avatar asked Jul 13 '11 02:07

Alex Brown


1 Answers

So after going through several iterations and searching the web, I have created this nice short one.

hotfactor= function(fac,by,n=10,o="other") {
   levels(fac)[rank(-xtabs(by~fac))[levels(fac)]>n] <- o
   fac
}

It's great for summarising data, and you can use it to access the great rcolorbrewer color schemes (which each have a limited number of carefully selected colors).


Usage notes:

fac should be a factor, and works best with no empty factor levels. You may want to run droplevels(as.factor(mydata)) first.

It doesn't sort the factor levels. for best results in barcharts you should run the following on the output factor.

x <- hotfactor(f,val)
x <- reorder(x,-val,sum)
like image 90
Alex Brown Avatar answered Nov 15 '22 22:11

Alex Brown