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I need to cut off the last seven characters of a string (a string that is stored in a hash). What is the easiest way to do that in perl? Many thanks in advance!
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We can use the chop() method to remove the last character of a string in Perl. This method removes the last character present in a string. It returns the character that is removed from the string, as the return value.
Perl chop() function is used to remove the last character of the input string and return the chopped character as an output to the user. Chop function has removed the last character from each element from the list, expression, and $_ if we have not specified any value with chop function in Perl.
The chop() function in Perl is used to remove the last character from the input string. Syntax: chop(String) Parameters: String : It is the input string whose last characters are removed. Returns: the last removed character.
With substr():
substr($string, 0, -7); I suggest you read the Perldoc page on substr() (which I linked to above) before just copying and pasting this into your code. It does what you asked, but substr() is a very useful and versatile function, and I suggest you understand everything you can use it for (by reading the documentation).
Also, in the future, please consider Googling your question (or, in the case of Perl, looking it up on Perldoc) before asking it here. You can find great resources on things like this without having to ask questions here. Not to put down your question, but it's pretty simple, and I think if you tried, you could find the answer on your own.
120
To remove the last 7 characters:
substr($str, -7) = ''; or the somewhat inelegant
substr($str, -7, length($str), ''); To get all but the last 7 characters:
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