I'm trying to modify an example of a simple forest plot by introducing facets according to a factor variable.
Assuming data of this structure:
test <- structure(list(characteristic = structure(c(1L, 2L, 3L, 1L, 2L ), .Label = c("Factor1", "Factor2", "Factor3"), class = "factor"), es = c(1.2, 1.4, 1.6, 1.3, 1.5), ci_low = c(1.1, 1.3, 1.5, 1.2, 1.4), ci_upp = c(1.3, 1.5, 1.7, 1.4, 1.6), label = structure(c(1L, 3L, 5L, 2L, 4L), .Label = c("1.2 (1.1, 1.3)", "1.3 (1.2, 1.4)", "1.4 (1.3, 1.5)", "1.5 (1.4, 1.6)", "1.6 (1.5, 1.7)"), class = "factor"), set = structure(c(1L, 1L, 1L, 2L, 2L), .Label = c("H", "S" ), class = "factor")), .Names = c("characteristic", "es", "ci_low", "ci_upp", "label", "set"), class = "data.frame", row.names = c(NA, -5L))
And running the code:
p <- ggplot(test, aes(x=characteristic, y=es, ymin=ci_low, ymax=ci_upp)) + geom_pointrange() + coord_flip() + geom_hline(aes(x=0), lty=2) + facet_wrap(~ set, ncol = 1) + theme_bw() + opts(strip.text.x = theme_text())
Produces output like that:
All good so far. However, I'd like to get rid of empty Factor3 level from my lower panel and cannot find a way to do that. Is there any way to do that?
Thanks for help.
facet_grid() forms a matrix of panels defined by row and column faceting variables. It is most useful when you have two discrete variables, and all combinations of the variables exist in the data. If you have only one variable with many levels, try facet_wrap() .
The facet_grid() function will produce a grid of plots for each combination of variables that you specify, even if some plots are empty. The facet_wrap() function will only produce plots for the combinations of variables that have values, which means it won't produce any empty plots.
Facet labels text element in theme() to element_blank() . Setting strip. text to element_blank() will remove all facet labels. You can also remove the labels across rows only with strip.
17.1 Facet wrap This is useful if you have a single variable with many levels and want to arrange the plots in a more space efficient manner. You can control how the ribbon is wrapped into a grid with ncol , nrow , as. table and dir . ncol and nrow control how many columns and rows (you only need to set one).
EDIT Updated to ggplot2 0.9.3
Here's another solution. It uses facet_grid
and space = "free"
; also it uses geom_point()
and geom_errorbarh()
, and thus there is no need for coord.flip()
. Also, the x-axis tick mark labels appear on the lower panel only. In the code below, the theme
command is not essential - it is used to rotate the strip text to appear horizontally. Using the test
dataframe from above, the following code should produce what you want:
library(ggplot2) p <- ggplot(test, aes(y = characteristic, x = es, xmin = ci_low, xmax = ci_upp)) + geom_point() + geom_errorbarh(height = 0) + facet_grid(set ~ ., scales = "free", space = "free") + theme_bw() + theme(strip.text.y = element_text(angle = 0)) p
The solution is based on the example on page 124 in Wickham's ggplot2 book.
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