How can I print integer in triangle form

Question

I want to print integer in triangle form which look like this

    1
   121
  12321

I tried this but I do not get the actual result

for($i=1;$i<=3;$i++)
 {
    for($j=3;$j>=$i;$j--)
    {
      echo "&nbsp;&nbsp;";
    }
   for($k=1;$k<=$i;$k++)
    {
      echo $k;
    }
   if($i>1)
    {
      for($m=$i; $m>=1; $m--)
         {
           echo $m;
         }
     }      
    echo "<br>";
}

Output of this code is:

   1
  1221
 123321

Where am I going wrong, please guide me.

Answer 1

Another integer solution:

$n = 9; 
print str_pad ("✭",$n," ",STR_PAD_LEFT) . PHP_EOL;
for ($i=0; $i<$n; $i++){
    print str_pad ("", $n - $i);
    for ($ii=-$i; $ii<=$i; $ii++){
      if ($i % 2 != 0 && $ii % 2 == 0)
        print "&#" . rand(10025,10059) . ";";
      else print $i - abs($ii) + 1;
    }
    print PHP_EOL;
}

        ✭
        1 
       1✬1 
      12321 
     1❊3✪3✳1 
    123454321 
   1✼3✶5❃5❈3✸1
  1234567654321 
 1✾3✯5✿7❉7✫5✷3✶1 
12345678987654321 

Or if you already have the string, you could do:

$n = 9; $s = "12345678987654321"; $i = 1;

while ($i <= $n)
   echo str_pad ("", $n-$i) . substr ($s,0,$i - 1) . substr ($s,-$i++) . PHP_EOL;

Answer 2

Your code should be this:

for($i=1;$i<=3;$i++)
 {
    for($j=3;$j>$i;$j--)
    {
      echo "&nbsp;&nbsp;";
    }
   for($k=1;$k<$i;$k++) /** removed = sign*/
    {
      echo $k;
    }
   if($i>=1) /**added = sign*/
    {
      for($m=$i; $m>=1; $m--)
         {
           echo $m;
         }
     }      
    echo "<br>";
}

Try this.

Details:

1. Your loop is not proper as in case of for($k=1;$k<=$i;$k++), this will print the repeated number when check the condition for less then and again for equals to. So remove the equals sign.

2. reason to add the eqaul sign in if($i>=1) is that the first element will not print if there will not be equals as first it will be print by for loop from where removed the equal sign.

Your output will be this:

   1
  121
 12321