How can I perform divison on a datetime.timedelta in python?

Question

I'd like to be able to do the following:

num_intervals = (cur_date - previous_date) / interval_length 

or

print (datetime.now() - (datetime.now() - timedelta(days=5)))        / timedelta(hours=12) # won't run, would like it to print '10' 

but the division operation is unsupported on timedeltas. Is there a way that I can implement divison for timedeltas?

Edit: Looks like this was added to Python 3.2 (thanks rincewind!): http://bugs.python.org/issue2706

Answer 1

Division and multiplication by integers seems to work out of the box:

>>> from datetime import timedelta >>> timedelta(hours=6) datetime.timedelta(0, 21600) >>> timedelta(hours=6) / 2 datetime.timedelta(0, 10800) 

Answer 2

Sure, just convert to a number of seconds (minutes, milliseconds, hours, take your pick of units) and do the division.

EDIT (again): so you can't assign to timedelta.__div__. Try this, then:

divtdi = datetime.timedelta.__div__ def divtd(td1, td2):     if isinstance(td2, (int, long)):         return divtdi(td1, td2)     us1 = td1.microseconds + 1000000 * (td1.seconds + 86400 * td1.days)     us2 = td2.microseconds + 1000000 * (td2.seconds + 86400 * td2.days)     return us1 / us2 # this does integer division, use float(us1) / us2 for fp division 

And to incorporate this into nadia's suggestion:

class MyTimeDelta:     __div__ = divtd 

Example usage:

>>> divtd(datetime.timedelta(hours = 12), datetime.timedelta(hours = 2)) 6 >>> divtd(datetime.timedelta(hours = 12), 2) datetime.timedelta(0, 21600) >>> MyTimeDelta(hours = 12) / MyTimeDelta(hours = 2) 6 

etc. Of course you could even name (or alias) your custom class timedelta so it gets used in place of the real timedelta, at least in your code.