Given two strings text1
and text2
:
public SOMEUSABLERETURNTYPE Compare(string text1, string text2) { // DO SOMETHING HERE TO COMPARE }
Examples:
First String: StackOverflow
Second String: StaqOverflow
Return: Similarity is 91%
The return can be in % or something like that.
First String: The simple text test
Second String: The complex text test
Return: The values can be considered equal
Any ideas? What is the best way to do this?
Levenshtein distance. A metric for measuring similarity between two strings. It is equal to the minimum number of operations required to transform a given string into another one.
The simplest way to check if two strings are equal in Python is to use the == operator. And if you are looking for the opposite, then != is what you need. That's it!
Typically, the Jaccard similarity coefficient (or index) is used to compare the similarity between two sets. For two sets, A and B , the Jaccard index is defined to be the ratio of the size of their intersection and the size of their union: J(A,B) = (A ∩ B) / (A ∪ B)
To calculate the similarity between two examples, you need to combine all the feature data for those two examples into a single numeric value. For instance, consider a shoe data set with only one feature: shoe size. You can quantify how similar two shoes are by calculating the difference between their sizes.
There are various different ways of doing this. Have a look at the Wikipedia "String similarity measures" page for links to other pages with algorithms.
I don't think any of those algorithms take sounds into consideration, however - so "staq overflow" would be as similar to "stack overflow" as "staw overflow" despite the first being more similar in terms of pronunciation.
I've just found another page which gives rather more options... in particular, the Soundex algorithm (Wikipedia) may be closer to what you're after.
Levenshtein distance is probably what you're looking for.
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