how can I make this coin flip simulation work based on user input? java eclipse

Question

I have this code, which allows me to simulate coin tosses, 0 being heads and 1 being tails or whichever you wish to interpret. When you run the program it randomly generates (in this case) 10 combinations of two coin tosses. What I wish to do is modify this program so that the user can ask how many times the coin will be tossed, the coin results will be shown and then he can be prompt to flip again.

public class Dice {
    public static void main(String[] args)
    {
        for (int i = 0; i <= 10; i++)
        {
            int benito1=(int)(Math.random()*2);
            int benito2=(int)(Math.random()*2);
            System.out.println(benito1 + " " +benito2);
        }
        System.out.println();
    }
}

Answer 1

something like this:

Scanner sc = new Scanner(System.in);
System.out.prinltn("Please enter a number");
int input = sc.nextInt(); 
while(input-->0)
   {
        int benito1=(int)(Math.random()*2);
              int benito2=(int)(Math.random()*2);
              System.out.println(benito1 + " " +benito2);
            }

Answer 2

Some thing like this :

public static void main(String[] args) {
        toss();
        System.out.println();
    }

    private static void toss() {
        Scanner get = new Scanner(System.in);
        System.out.println("Enter the limit ...");
        int limit = get.nextInt();
        for (int i = 0; i < limit; i++) {
            int benito1 = (int) (Math.random() * 2);
            int benito2 = (int) (Math.random() * 2);
            System.out.println(benito1 + " " + benito2);
        }
        System.out.println("would you like to continue>");
        String ans = get.next();
        if(ans.equalsIgnoreCase("y") || ans.equalsIgnoreCase("yes")) {
            toss();
        }

    }