How can I make gson exclude my object's superclass?

Question

Im trying to serialize/deserialize using Gson. I don't want the super class (which is abstract) to be considered, the problem is that I don't have access to the super class code.

I've tried with an ExclusionStrategy but it didn't work.

private class SuperClassExclusionStrategy implements ExclusionStrategy {

        @Override
        public boolean shouldSkipClass(Class<?> clazz) {
            return clazz.equals(SuperClass.class);
        }

        @Override
        public boolean shouldSkipField(FieldAttributes field) {
            return false;
        }

    }

How can I solve this?

Edit:

I need the fields in the superclass to be ignored, this is because I am getting this error: MyClass declares multiple JSON fields named. I can not change the conflicting fields name.

Solution:

Solved with the following strategy:

private static class SuperClassExclusionStrategy implements ExclusionStrategy {

  public boolean shouldSkipClass(Class<?> clazz) {
   return false;
  }

  public boolean shouldSkipField(FieldAttributes field) {
   return field.getDeclaringClass().equals(MySuperClass.class) && field.getName()
    .equals("id");
  }
 }

Answer 1

From the Gson documentation

Exclude fields and objects based on a particular class type:

private static class SpecificClassExclusionStrategy implements ExclusionStrategy {
    private final Class<?> excludedThisClass;

    public SpecificClassExclusionStrategy(Class<?> excludedThisClass) {
        this.excludedThisClass = excludedThisClass;
    }

    public boolean shouldSkipClass(Class<?> clazz) {
        return excludedThisClass.equals(clazz);
   }

   public boolean shouldSkipField(FieldAttributes f) {
        return excludedThisClass.equals(f.getDeclaringClass()());
   }
}