How can I log current line, and stack info with Python?

Question

I have logging function as follows.

logging.basicConfig(     filename = fileName,     format = "%(levelname) -10s %(asctime)s %(message)s",     level = logging.DEBUG )  def printinfo(string):     if DEBUG:         logging.info(string)  def printerror(string):     if DEBUG:         logging.error(string)     print string 

I need to login the line number, stack information. For example:

1: def hello(): 2:    goodbye() 3: 4: def goodbye(): 5:    printinfo()  ---> Line 5: goodbye()/hello() 

How can I do this with Python?

SOLVED

def printinfo(string):     if DEBUG:         frame = inspect.currentframe()         stack_trace = traceback.format_stack(frame)         logging.debug(stack_trace[:-1])     if LOG:         logging.info(string) 

gives me this info which is exactly what I need.

DEBUG      2011-02-23 10:09:13,500 [   '  File "/abc.py", line 553, in <module>\n    runUnitTest(COVERAGE, PROFILE)\n',    '  File "/abc.py", line 411, in runUnitTest\n    printinfo(string)\n'] 

Answer 1

Current function name, module and line number you can do simply by changing your format string to include them.

logging.basicConfig(     filename = fileName,     format = "%(levelname) -10s %(asctime)s %(module)s:%(lineno)s %(funcName)s %(message)s",     level = logging.DEBUG ) 

Most people only want the stack when logging an exception, and the logging module does that automatically if you call logging.exception(). If you really want stack information at other times then you will need to use the traceback module for extract the additional information you need.

Answer 2

import inspect import traceback  def method():    frame = inspect.currentframe()    stack_trace = traceback.format_stack(frame)    print ''.join(stack_trace) 

Use stack_trace[:-1] to avoid including method/printinfo in the stack trace.