How can I have multiple random outputs from a single line of code (python)

Question

How would I have a single line of code generate more than one random choice from a chosen list?

btw I do have import random at the top of the code

here is my code:

(R[0] = "RED", O[0] = "ORANGE", etc.)

ColourList = [R[0],O[0],Y[0],G[0],B[0],I[0],V[0]]
ColourSeq = random.choice(ColourList)
print(ColourSeq)

I know at the moment I have only asked it to give me one output, but I would like it to be able to give me four of the items from ColourList in just one line of code. There can be duplicate outputs.

Answer 1

You can use random.choices instead of random.choice. It is new in version 3.6.

ColourList = [R[0],O[0],Y[0],G[0],B[0],I[0],V[0]]
ColourSeq = random.choices(ColourList, k=6)
print(ColourSeq)

Answer 2

If you want to allow duplicate values, you can't use random.sample(). You can use a list comprehension:

ColourList = [R[0],O[0],Y[0],G[0],B[0],I[0],V[0]]
ColourSeq = [random.choice(ColourList) for x in range(4)]
print(ColourSeq)

---

If you want to print those values on separate lines, without the various additions of the list, replace the print statement with

print(*ColourSeq, sep='\n')

or with the longer but clearer

for v in ColourSeq:
    print(v)

If you want them printed on the same line but with the list stuff removed, just use the simple

print(*ColourSeq)