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Is there any way to get milliseconds and its fraction part from 1970 using time.h in c language?
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A simple solution is to get the timedelta object by finding the difference of the given datetime with Epoch time, i.e., midnight 1 January 1970. To obtain time in milliseconds, you can use the timedelta. total_seconds() * 1000 .
Convert from human-readable date to epoch long epoch = new java.text.SimpleDateFormat("MM/dd/yyyy HH:mm:ss").parse("01/01/1970 01:00:00").getTime() / 1000; Timestamp in seconds, remove '/1000' for milliseconds.
In computing, Unix time (also known as Epoch time, Posix time, seconds since the Epoch, Unix timestamp or UNIX Epoch time) is a system for describing a point in time. It is the number of seconds that have elapsed since the Unix epoch, excluding leap seconds. The Unix epoch is 00:00:00 UTC on 1 January 1970.
Unix Time in Milliseconds Another option is to represent timestamps using the number of milliseconds since the Unix epoch instead of the number of seconds.
This works on Ubuntu Linux:
#include <sys/time.h> ... struct timeval tv; gettimeofday(&tv, NULL); unsigned long long millisecondsSinceEpoch = (unsigned long long)(tv.tv_sec) * 1000 + (unsigned long long)(tv.tv_usec) / 1000; printf("%llu\n", millisecondsSinceEpoch); At the time of this writing, the printf() above is giving me 1338850197035. You can do a sanity check at the TimestampConvert.com website where you can enter the value to get back the equivalent human-readable time (albeit without millisecond precision).
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If you want millisecond resolution, you can use gettimeofday() in Posix. For a Windows implementation see gettimeofday function for windows.
#include <sys/time.h> ... struct timeval tp; gettimeofday(&tp); long int ms = tp.tv_sec * 1000 + tp.tv_usec / 1000; If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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