I tried
$dtToday = DateTime::createFromFormat('Y-m-d', date('Y-m-d'));
but when I output it
die($dtToday->format('d M Y g:i:s a'));
I still get the time eg "22 Jan 2011 4:53:59 pm". Why is that?
UPDATE
Ah... many people misunderstood me, my bad, I forgot to point out the main point. I created the date with just the date portion, I don't want the time. So I'd expect something like
22 Jan 2011 12:00:00 am
The time() function returns the current time in the number of seconds since the Unix Epoch (January 1 1970 00:00:00 GMT).
Answer: Use the PHP date() Function You can simply use the PHP date() function to get the current data and time in various format, for example, date('d-m-y h:i:s') , date('d/m/y H:i:s') , and so on.
Getting the Current Time Stampconst currentDate = new Date(); const timestamp = currentDate. getTime(); In JavaScript, a time stamp is the number of milliseconds that have passed since January 1, 1970.
MySQL function NOW() returns the current timestamp.
You can call ->setTime(0, 0)
to zero out the time portion:
$date = DateTime::createFromFormat('Y-m-d', '2011-01-22')->setTime(0, 0);
echo $date->format('d M Y g:i:s a');
// 22 Jan 2011 12:00:00 am
See the documentation for DateTime::createFromFormat
:
If format does not contain the character ! then portions of the generated time which are not specified in format will be set to the current system time.
If you do the following function call, you'll get the result you expect:
$dtToday = DateTime::createFromFormat('!Y-m-d', date('Y-m-d'));
Today's start timestamp
$todayStartTS = strtotime(date('Y-m-d', time()) . ' 00:00:00');
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