How can I get the request URL from a Java Filter?

Question

I am trying to write a filter that can retrieve the request URL, but I'm not sure how to do so.

Here is what I have so far:

import javax.servlet.*; import javax.servlet.http.HttpServletRequest; import java.io.IOException;  public class MyFilter implements Filter {     public void init(FilterConfig config) throws ServletException { }      public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws ServletException, IOException {         chain.doFilter(request, response);          String url = ((HttpServletRequest) request).getPathTranslated();         System.out.println("Url: " + url);     }      public void destroy() { } } 

When I hit a page on my server, the only output I see is "Url: null".

What is the correct way to get the requested URL from a given ServletRequest object in a Filter?

Answer 1

Is this what you're looking for?

if (request instanceof HttpServletRequest) {  String url = ((HttpServletRequest)request).getRequestURL().toString();  String queryString = ((HttpServletRequest)request).getQueryString(); } 

To Reconstruct:

System.out.println(url + "?" + queryString); 

Info on HttpServletRequest.getRequestURL() and HttpServletRequest.getQueryString().