I want to list only the objects in a bucket that aren't buckets themselves. Is there a way of doing this short of parsing out the results of ListBucket?
Sign in to the AWS Management Console and open the Amazon S3 console at https://console.aws.amazon.com/s3/ . In the Buckets list, choose the name of the bucket that you want. Choose Properties. Navigate to the S3 Intelligent-Tiering Archive configurations section and choose Create configuration.
Amazon S3 Standard-Infrequent Access (S3 Standard-IA) S3 Standard-IA is for data that is accessed less frequently, but requires rapid access when needed. S3 Standard-IA offers the high durability, high throughput, and low latency of S3 Standard, with a low per GB storage price and per GB retrieval charge.
Navigate to the Amazon S3 bucket or folder that contains the objects that you want to delete. Select the check box to the left of the names of the objects that you want to delete. Choose Actions and choose Delete from the list of options that appears. Alternatively, choose Delete from the options in the upper right.
Amazon Simple Storage Service (Amazon S3) is an object storage service that offers industry-leading scalability, data availability, security, and performance.
objects in a bucket that aren't buckets themselves
Buckets can't contain other buckets. Do you mean folders? S3 doesn't have a concept of folders either.
You can have 100 buckets per S3 account and each bucket can contain an unlimited number of objects/files. If you name your files with /
's in the filename, the AWS GUI tools (eg AWS Console, BucketExplorer etc) will interpret each section as a virtual folder. eg
A file named folder1/folder2/myfile.jpg
will be stored in S3 as a 'flat' file with that name, but in the GUI tools it will appear as though a file named myfile.jpg
is 2 subfolders down in folder1/folder2
.
You can use the prefix
and delimiter
parameters to parse the results of a GET Bucket (List Objects) call. The same options are available in any of the SDKs too.
UPDATE to answer comment.
Assuming our S3 bucket looks like this:
mybucket
folder1
file1.txt
file2.txt
folder2
file3.txt
file4.txt
folder3
file5.txt
file6.txt
Using prefix = "folder1/"
would return all 6 files : file1.txt
to file6.txt
.
Using a prefix = "folder1/"
and a delimiter = "/"
would return 2 files:
file1.txt
file2.txt
And the CommonPrefixes
collection of the response with contain
folder1/folder2/
folder1/folder3/
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