how can I get filenames without directory name

Question

how can I list only file names in a directory without directory info in the result? I tried

for file in glob.glob(dir+filetype):
    print file

give me result /path_name/1.log,/path_name/2.log,.... but what I do need is file name only: 1.log, 2.log, etc. I do not need the directory info in the result. is there a simple way to get rid of the path info? I don't want to some substr on the result. Thank you!

Answer 1

os.path.basename:

Return the base name of pathname path. This is the second element of the pair returned by passing path to the function split(). Note that the result of this function is different from the Unix basename program; where basename for '/foo/bar/' returns 'bar', the basename() function returns an empty string ('').

So:

>>> os.path.basename('/path_name/1.log,/path_name/2.log')
'2.log'

Answer 2

import os

# Do not use 'dir' as a variable name, as it's a built-in function
directory = "path"
filetype  = "*.log"

# ['foo.log', 'bar.log']
[f for f in os.listdir(directory) if f.endswith(filetype[1:])]