How can I get access to a Django Model field verbose name dynamically?

Question

I'd like to have access to one my model field verbose_name.

I can get it by the field indice like this

model._meta._fields()[2].verbose_name

but I need to get it dynamically. Ideally it would be something like this

model._meta._fields()['location_x'].verbose_name

I've looked at a few things but I just can't find it.

Answer 1

For Django < 1.10:

model._meta.get_field_by_name('location_x')[0].verbose_name

Answer 2

model._meta.get_field('location_x').verbose_name

Answer 3

For Django 1.11 and 2.0:

MyModel._meta.get_field('my_field_name').verbose_name

More info in the Django doc

Answer 4

The selected answer gives a proxy object which might look as below.

<django.utils.functional.__proxy__ object at 0x{SomeMemoryLocation}>

If anyone is seeing the same, you can find the string for the verbose name in the title() member function of the proxy object.

model._meta.get_field_by_name(header)[0].verbose_name.title()

A better way to write this would be:

model._meta.get_field(header).verbose_name.title()

where header will be the name of the field you are interested in. i.e., 'location-x' in OPs context.

NOTE: Developers of Django also feel that using get_field is better and thus have depreciated get_field_by_name in Django 1.10. Thus I would suggest using get_field no matter what version of Django you use.

Answer 5

model._meta.get_field_by_name('location_x')[0].verbose_name

Answer 6

You can also use:

Model.location_x.field.verbose_name

Model being the class name. I tested this on my Animal model:

Animal.sale_price.field.verbose_name

Animal.sale_price returns a DeferredAttribute, which has several meta data, like the verbose_name

Note: I'm using Django 3.1.5

Answer 7

If you want to iterate on all the fields you need to get the field:

for f in BotUser._meta.get_fields():
    if hasattr(f, 'verbose_name'):
        print(f.verbose_name)