How can I get a uitableViewCell by indexPath?

Question

How can I get a UITableViewCell by indexPath? Like this:

I use the UIActionSheet, when I click confirm UIButton I want to change the cell text.

The nowIndex I define as a property

- (void)actionSheet:(UIActionSheet *)actionSheet clickedButtonAtIndex:(NSInteger)buttonIndex {     if (buttonIndex == 0)     {         NSInteger section =  [nowIndex section];         NSInteger row = [nowIndex row];         NSDateFormatter *formatter = [[[NSDateFormatter alloc] init] autorelease];         formatter.dateFormat = @"yyyy-MM-dd";          if (section == 0)         {             if (row == 0)             {              }             else if (row == 1)             {                 UILabel *content = (UILabel *)[[(UITableView *)[actionSheet ] cellForRowAtIndexPath:nowIndex] viewWithTag:contentTag];                 content.text = [formatter stringFromDate:checkInDate.date];             }             else if (row == 2)             {              }         }     } } 

Answer 1

[(UITableViewCell *)[(UITableView *)self cellForRowAtIndexPath:nowIndex] 

will give you uitableviewcell. But I am not sure what exactly you are asking for! Because you have this code and still you asking how to get uitableviewcell. Some more information will help to answer you :)

ADD: Here is an alternate syntax that achieves the same thing without the cast.

UITableViewCell *cell = [self.tableView cellForRowAtIndexPath:nowIndex]; 

Answer 2

Finally, I get the cell using the following code:

UITableViewCell *cell = (UITableViewCell *)[(UITableView *)self.view cellForRowAtIndexPath:nowIndex]; 

Because the class is extended UITableViewController:

@interface SearchHotelViewController : UITableViewController 

So, the self is "SearchHotelViewController".