How can I get a JavaScript stack trace when I throw an exception?

Question

If I throw a JavaScript exception myself (eg, throw "AArrggg"), how can I get the stack trace (in Firebug or otherwise)? Right now I just get the message.

edit: As many people below have posted, it is possible to get a stack trace for a JavaScript exception but I want to get a stack trace for my exceptions. For example:

function foo() {     bar(2); } function bar(n) {     if (n < 2)         throw "Oh no! 'n' is too small!"     bar(n-1); } 

When foo is called, I want to get a stack trace which includes the calls to foo, bar, bar.

Answer 1

Edit 2 (2017):

In all modern browsers you can simply call: console.trace(); (MDN Reference)

Edit 1 (2013):

A better (and simpler) solution as pointed out in the comments on the original question is to use the stack property of an Error object like so:

function stackTrace() {     var err = new Error();     return err.stack; } 

This will generate output like this:

DBX.Utils.stackTrace@http://localhost:49573/assets/js/scripts.js:44 DBX.Console.Debug@http://localhost:49573/assets/js/scripts.js:9 .success@http://localhost:49573/:462 x.Callbacks/c@http://localhost:49573/assets/js/jquery-1.10.2.min.js:4 x.Callbacks/p.fireWith@http://localhost:49573/assets/js/jquery-1.10.2.min.js:4 k@http://localhost:49573/assets/js/jquery-1.10.2.min.js:6 .send/r@http://localhost:49573/assets/js/jquery-1.10.2.min.js:6 

Giving the name of the calling function along with the URL, its calling function, and so on.

Original (2009):

A modified version of this snippet may somewhat help:

function stacktrace() {    function st2(f) {     return !f ? [] :          st2(f.caller).concat([f.toString().split('(')[0].substring(9) + '(' + f.arguments.join(',') + ')']);   }   return st2(arguments.callee.caller); }