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How can I find out what 500 error am I getting in Django?

When I visit a page (http://68.123.151.234/static/quickstart.html) in my Django application served on a server spawned by Django, the page reads

A server error occurred.  Please contact the administrator.

And I receive this traceback.

Traceback (most recent call last):
  File "/usr/lib/python2.7/wsgiref/handlers.py", line 85, in run
    self.result = application(self.environ, self.start_response)
  File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/wsgi.py", line 241, in __call__
    response = self.get_response(request)
  File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/base.py", line 153, in get_response
    response = self.handle_uncaught_exception(request, resolver, sys.exc_info())
  File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/base.py", line 228, in handle_uncaught_exception
    return callback(request, **param_dict)
  File "/usr/local/lib/python2.7/dist-packages/django/utils/decorators.py", line 91, in _wrapped_view
    response = view_func(request, *args, **kwargs)
  File "/usr/local/lib/python2.7/dist-packages/django/views/defaults.py", line 32, in server_error
    t = loader.get_template(template_name) # You need to create a 500.html template.
  File "/usr/local/lib/python2.7/dist-packages/django/template/loader.py", line 145, in get_template
    template, origin = find_template(template_name)
  File "/usr/local/lib/python2.7/dist-packages/django/template/loader.py", line 138, in find_template
    raise TemplateDoesNotExist(name)
TemplateDoesNotExist: 500.html
[17/May/2012 11:31:45] "GET /static/quickstart.html HTTP/1.1" 500 59
Traceback (most recent call last):
  File "/usr/lib/python2.7/wsgiref/handlers.py", line 85, in run
    self.result = application(self.environ, self.start_response)
  File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/wsgi.py", line 241, in __call__
    response = self.get_response(request)
  File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/base.py", line 153, in get_response
    response = self.handle_uncaught_exception(request, resolver, sys.exc_info())
  File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/base.py", line 228, in handle_uncaught_exception
    return callback(request, **param_dict)
  File "/usr/local/lib/python2.7/dist-packages/django/utils/decorators.py", line 91, in _wrapped_view
    response = view_func(request, *args, **kwargs)
  File "/usr/local/lib/python2.7/dist-packages/django/views/defaults.py", line 32, in server_error
    t = loader.get_template(template_name) # You need to create a 500.html template.
  File "/usr/local/lib/python2.7/dist-packages/django/template/loader.py", line 145, in get_template
    template, origin = find_template(template_name)
  File "/usr/local/lib/python2.7/dist-packages/django/template/loader.py", line 138, in find_template
    raise TemplateDoesNotExist(name)
TemplateDoesNotExist: 500.html

This traceback only tells me that I need a 500 template - not what the actual server error is. How can I find out what the server error was?

I checked out Django documentation (https://docs.djangoproject.com/en/1.4/topics/http/views/), which directs me to create a 500 error template as a potential solution. However, it gives no instructions as to how to display the error within such a template.

like image 810
dangerChihuahua007 Avatar asked May 17 '12 16:05

dangerChihuahua007


1 Answers

A basic 500.html which is convenient and useful would, as Alasdair said, potentially reveal something sensitive.

However, if debugging over the web in a responsible way is the objective, a basic nondefault500.html template for your site template dir would look like

<html><head><body>
<!-- starting with sys.exc_info but hey, it's python -->
Type: {{ type }} <br />
Value: {{ value }} <br />
Traceback: {{ traceback }} <br />
</body></head></html>

and the new handler would populate that context as such:

def this_server_error(request, template_name='nondefault500.html'):
    """
    500 error handler.

    Templates: `500.html`
    Context: sys.exc_info() results
     """
    t = loader.get_template(template_name) # You need to create a 500.html template.
    ltype,lvalue,ltraceback = sys.exc_info()
    sys.exc_clear() #for fun, and to point out I only -think- this hasn't happened at 
                    #this point in the process already
    return http.HttpResponseServerError(t.render(Context({'type':ltype,'value':lvalue,'traceback':ltraceback})))

and there would need to be a URLconf adjustment made,

handler500 = 'mysite.views.this_server_error'
like image 152
rhoyerboat Avatar answered Sep 24 '22 15:09

rhoyerboat