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I'm creating a unit converter, and I want to put all of the conversion functions into their own file. Using ES6 export, is there any way to export all of the functions in the file with their default names using only one line? For example:
export default all;
The functions are all just in the file, not within an object.
991
Use named exports to export all functions from a file, e.g. export function A() {} and export function B() {} . The exported functions can be imported by using a named import as import {A, B} from './another-file. js' .
Use named exports to export a function in JavaScript, e.g. export function sum() {} . The exported function can be imported by using a named import as import {sum} from './another-file. js' . You can use as many named exports as necessary in a file.
The export statement is used in Javascript modules to export functions, objects, or primitive values from one module so that they can be used in other programs (using the 'import' statement). A module encapsulates related code into a single unit of code. All functions related to a single module are contained in a file.
No, there's no wildcard export (except when you're re-exporting everything from another module, but that's not what you're asking about).
Simply put export in front of each function declaration you want exported, e.g.
export function foo() { // ... } export function bar() { // ... } ...or of course, if you're using function expressions:
export var foo = function() { // ... }; export let bar = () => { // ... }; export const baz = value => { // ... }; If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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