How can I display rows values in columns sql server?

Question

SQL FIDDLE DEMO HERE

I have this table structure for SheduleWorkers table:

    CREATE TABLE SheduleWorkers
    (
         [Name] varchar(250),
         [IdWorker] varchar(250),    
         [IdDepartment] int,
         [IdDay] int,
         [Day] varchar(250)
    );


INSERT INTO SheduleWorkers ([Name],  [IdWorker],  [IdDepartment], [IdDay], [Day])
values 
('Sam', '001', 5, 1, 'Monday'),
('Lucas', '002', 5, 2, 'Tuesday'),
('Maria', '003', 5, 1, 'Monday'),
('José', '004', 5, 3, 'Wednesday'),
('Julianne', '005', 5, 3, 'Wednesday'),
('Elisa', '006', 18, 1, 'Monday'),
('Gabriel', '007', 23, 5, 'Friday');

I need to display for each week day the names of workers in the department 5 that works in this day, like this:

MONDAY   TUESDAY   WEDNESDAY  THURSDAY  FRIDAY  SATURDAY
------   -------   ---------  --------  ------  -------
Sam       Lucas    Jose       
Maria              Julianne

How can I get this result, I accept suggestions, thanks.

Answer 1

DECLARE @SheduleWorkers TABLE
    (
      [Name] VARCHAR(250) ,
      [IdWorker] VARCHAR(250) ,
      [IdDepartment] INT ,
      [IdDay] INT ,
      [Day] VARCHAR(250)
    );


INSERT  INTO @SheduleWorkers
        ( [Name], [IdWorker], [IdDepartment], [IdDay], [Day] )
VALUES  ( 'Sam', '001', 5, 1, 'Monday' ),
        ( 'Lucas', '002', 5, 2, 'Tuesday' ),
        ( 'Maria', '003', 5, 1, 'Monday' ),
        ( 'José', '004', 5, 3, 'Wednesday' ),
        ( 'Julianne', '005', 5, 3, 'Wednesday' ),
        ( 'Elisa', '006', 18, 1, 'Monday' ),
        ( 'Gabriel', '007', 23, 5, 'Friday' );

;
WITH    cte
          AS ( SELECT   Name ,
                        Day ,
                        ROW_NUMBER() OVER ( PARTITION BY Day ORDER BY [IdWorker] ) AS rn
               FROM     @SheduleWorkers
             )
    SELECT  [MONDAY] ,
            [TUESDAY] ,
            [WEDNESDAY] ,
            [THURSDAY] ,
            [FRIDAY] ,
            [SATURDAY]
    FROM    cte PIVOT( MAX(Name) FOR day IN ( [MONDAY], [TUESDAY], [WEDNESDAY],
                                              [THURSDAY], [FRIDAY], [SATURDAY] ) ) p

Output:

MONDAY  TUESDAY WEDNESDAY   THURSDAY    FRIDAY  SATURDAY
Sam     Lucas   José        NULL        Gabriel NULL
Maria   NULL    Julianne    NULL        NULL    NULL
Elisa   NULL    NULL        NULL        NULL    NULL

The main idea is row_number window function in the common table expression, which will give you as many rows as there are maximum duplicates across a day.

Answer 2

You can use pivot for this. Please use below query for your problem. And use Partition.

SELECT  [Monday] , [Tuesday] , [Wednesday] , [Thursday] , [Friday], [SATURDAY]
FROM 
(SELECT [Day],[Name],RANK() OVER (PARTITION BY [Day] ORDER BY [Day],[Name]) as rnk
 FROM SheduleWorkers) p
 PIVOT(
Min([Name])
FOR [Day] IN
( [Monday] , [Tuesday] , [Wednesday] , [Thursday] , [Friday], [SATURDAY]  )
) AS pvt