How can I delete an item from an array in VB.NET?
pop() function: This method is use to remove elements from the end of an array. shift() function: This method is use to remove elements from the start of an array. splice() function: This method is use to remove elements from the specific index of an array.
Find the index of the array element you want to remove using indexOf , and then remove that index with splice . The splice() method changes the contents of an array by removing existing elements and/or adding new elements. The second parameter of splice is the number of elements to remove.
You can use unset() function which removes the element from an array and then use array_values() function which indexes the array numerically.
As Heinzi said, an array has a fixed size. In order to 'remove an item' or 'resize' it, you'll have to create a new array with the desired size and copy the items you need as appropriate.
Here's code to remove an item from an array:
<System.Runtime.CompilerServices.Extension()> _ Function RemoveAt(Of T)(ByVal arr As T(), ByVal index As Integer) As T() Dim uBound = arr.GetUpperBound(0) Dim lBound = arr.GetLowerBound(0) Dim arrLen = uBound - lBound If index < lBound OrElse index > uBound Then Throw New ArgumentOutOfRangeException( _ String.Format("Index must be from {0} to {1}.", lBound, uBound)) Else 'create an array 1 element less than the input array Dim outArr(arrLen - 1) As T 'copy the first part of the input array Array.Copy(arr, 0, outArr, 0, index) 'then copy the second part of the input array Array.Copy(arr, index + 1, outArr, index, uBound - index) Return outArr End If End Function
You can use it as such:
Module Module1 Sub Main() Dim arr = New String() {"abc", "mno", "xyz"} arr.RemoveAt(1) End Sub End Module
The code above removes the second element ("mno"
) [which has an index of 1] from the array.
You need to be developing in .NET 3.5 or higher in order to use the extension method. If you're using .NET 2.0 or 3.0, you can call the method as such
arr = RemoveAt(arr, 1)
I hope this is what you need.
After running tests based on ToolMakerSteve's comment it appears the initial code does not modify the array you want to update because of the ByVal
used in the function's declaration. However, writing code like arr = arr.RemoveAt(1)
or arr = RemoveAt(arr, 1)
does modify the array because it reassigns the modified array to the original.
Find below the updated method (subroutine) for removing an element from an array.
<System.Runtime.CompilerServices.Extension()> _ Public Sub RemoveAt(Of T)(ByRef arr As T(), ByVal index As Integer) Dim uBound = arr.GetUpperBound(0) Dim lBound = arr.GetLowerBound(0) Dim arrLen = uBound - lBound If index < lBound OrElse index > uBound Then Throw New ArgumentOutOfRangeException( _ String.Format("Index must be from {0} to {1}.", lBound, uBound)) Else 'create an array 1 element less than the input array Dim outArr(arrLen - 1) As T 'copy the first part of the input array Array.Copy(arr, 0, outArr, 0, index) 'then copy the second part of the input array Array.Copy(arr, index + 1, outArr, index, uBound - index) arr = outArr End If End Sub
Usage of the method is similar to the original, except there is no return value this time so trying to assign an array from the return value will not work because nothing is returned.
Dim arr = New String() {"abc", "mno", "xyz"} arr.RemoveAt(1) ' Output: {"abc", "mno"} (works on .NET 3.5 and higher) RemoveAt(arr, 1) ' Output: {"abc", "mno"} (works on all versions of .NET fx) arr = arr.RemoveAt(1) 'will not work; no return value arr = RemoveAt(arr, 1) 'will not work; no return value
Note:
I use a temporary array for the process because it makes my intentions clear and that is exactly what VB.NET does behind the scenes when you do Redim Preserve
. If you would like to modify the array in-place using Redim Preserve
, see ToolmakerSteve's answer.
The RemoveAt
methods written here are extension methods. In order for them to work, you will have to paste them in a Module
. Extension methods will not work in VB.NET if they are placed in a Class
.
Important If you will be modifying your array with lots of 'removes', it is highly recommended to use a different data structure such as List(Of T)
as suggested by other answerers to this question.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With