I would like to create the following vector sequence.
0 1 0 0 2 0 0 0 3 0 0 0 0 4
My thought was to create 0
first with rep()
but not sure how to add the 1:4
.
Create a diagonal matrix, take the upper triangle, and remove the first element:
d <- diag(0:4)
d[upper.tri(d, TRUE)][-1L]
# [1] 0 1 0 0 2 0 0 0 3 0 0 0 0 4
If you prefer a one-liner that makes no global assignments, wrap it up in a function:
(function() { d <- diag(0:4); d[upper.tri(d, TRUE)][-1L] })()
# [1] 0 1 0 0 2 0 0 0 3 0 0 0 0 4
And for code golf purposes, here's another variation using d
from above:
d[!lower.tri(d)][-1L]
# [1] 0 1 0 0 2 0 0 0 3 0 0 0 0 4
rep
and rbind
up to their old tricks:
rep(rbind(0,1:4),rbind(1:4,1))
#[1] 0 1 0 0 2 0 0 0 3 0 0 0 0 4
This essentially creates 2 matrices, one for the value, and one for how many times the value is repeated. rep
does not care if an input is a matrix, as it will just flatten it back to a vector going down each column in order.
rbind(0,1:4)
# [,1] [,2] [,3] [,4]
#[1,] 0 0 0 0
#[2,] 1 2 3 4
rbind(1:4,1)
# [,1] [,2] [,3] [,4]
#[1,] 1 2 3 4
#[2,] 1 1 1 1
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