How can I create a UIColor from a hex string?

Question

How can I create a UIColor from a hexadecimal string format, such as #00FF00?

Answer 1

I've found the simplest way to do this is with a macro. Just include it in your header and it's available throughout your project.

#define UIColorFromRGB(rgbValue) [UIColor colorWithRed:((float)((rgbValue & 0xFF0000) >> 16))/255.0 green:((float)((rgbValue & 0xFF00) >> 8))/255.0 blue:((float)(rgbValue & 0xFF))/255.0 alpha:1.0] 

uicolor macro with hex values

Also formatted version of this code:

#define UIColorFromRGB(rgbValue) \ [UIColor colorWithRed:((float)((rgbValue & 0xFF0000) >> 16))/255.0 \                 green:((float)((rgbValue & 0x00FF00) >>  8))/255.0 \                  blue:((float)((rgbValue & 0x0000FF) >>  0))/255.0 \                 alpha:1.0] 

Usage:

label.textColor = UIColorFromRGB(0xBC1128); 

Swift:

static func UIColorFromRGB(_ rgbValue: Int) -> UIColor! {     return UIColor(         red: CGFloat((Float((rgbValue & 0xff0000) >> 16)) / 255.0),         green: CGFloat((Float((rgbValue & 0x00ff00) >> 8)) / 255.0),         blue: CGFloat((Float((rgbValue & 0x0000ff) >> 0)) / 255.0),         alpha: 1.0) } 

Answer 2

A concise solution:

// Assumes input like "#00FF00" (#RRGGBB). + (UIColor *)colorFromHexString:(NSString *)hexString {     unsigned rgbValue = 0;     NSScanner *scanner = [NSScanner scannerWithString:hexString];     [scanner setScanLocation:1]; // bypass '#' character     [scanner scanHexInt:&rgbValue];     return [UIColor colorWithRed:((rgbValue & 0xFF0000) >> 16)/255.0 green:((rgbValue & 0xFF00) >> 8)/255.0 blue:(rgbValue & 0xFF)/255.0 alpha:1.0]; }