How can I create a new instance of DateTime in specific time zone?

Question

Given a specific TimeZoneInfo instance how can I create a new DateTime instance in the specified time zone? For example if I have:

var tz = TimeZoneInfo.FindSystemTimeZoneById("US Eastern Standard Time");
var date = new DateTime(2017, 1, 1, 0, 0, 0, DateTimeKind.Unspecified);
Console.WriteLine(TimeZoneInfo.ConvertTime(date, tz));

I am always getting 12/31/2016 7:00:00 PM regardless of what DateTimeKind I define (Utc, Local or Unspecified).

How can I declare a new DateTime that will be January 1st of 2017 at 0:00:00 in US Eastern Standard Time?

Answer 1

You can use TimeZoneInfo to retrieve your zone

You can find timezones here

var zn = TimeZoneInfo.FindSystemTimeZoneById("Eastern Standard Time");

to express that you are using a local eastern standard time use DateTimeOffset struct instead of DateTime

DateTimeOffset dateTimeOffset = new DateTimeOffset(new DateTime(2017, 1, 1, 0, 0, 0, DateTimeKind.Unspecified), zn.BaseUtcOffset); 

Why DateTimeOffset

DateTimeOffset is a representation of instantaneous time (also known as absolute time).

Answer 2

you can use the timezoneID as you are using it to specify what timezone you want to create your datetime object.

TimeZoneInfo tzone= TimeZoneInfo.FindSystemTimeZoneById("Eastern Standard 
Time");
DateTime dt = DateTime.Now();

later you just convert the datetime to your required timezone.

var datetime2 = TimeZoneInfo.ConvertTimeFromUtc(dt , tzone);

this is the link where you can find all timezones ID. TimeZoneIDs

Thank you, hope this can help you.