I have a lot of date strings like Mon, 16 Aug 2010 24:00:00
and some of them are in 00-23
hour format and some of them in 01-24
hour format. I want to get a list of date objects of them, but when I try to transform the example string into a date object, I have to transform it from Mon, 16 Aug 2010 24:00:00
to Tue, 17 Aug 2010 00:00:00
. What is the easiest way?
import email.utils as eutils
import time
import datetime
ntuple=eutils.parsedate('Mon, 16 Aug 2010 24:00:00')
print(ntuple)
# (2010, 8, 16, 24, 0, 0, 0, 1, -1)
timestamp=time.mktime(ntuple)
print(timestamp)
# 1282017600.0
date=datetime.datetime.fromtimestamp(timestamp)
print(date)
# 2010-08-17 00:00:00
print(date.strftime('%a, %d %b %Y %H:%M:%S'))
# Tue, 17 Aug 2010 00:00:00
Since you say you have a lot of these to fix, you should define a function:
def standardize_date(date_str):
ntuple=eutils.parsedate(date_str)
timestamp=time.mktime(ntuple)
date=datetime.datetime.fromtimestamp(timestamp)
return date.strftime('%a, %d %b %Y %H:%M:%S')
print(standardize_date('Mon, 16 Aug 2010 24:00:00'))
# Tue, 17 Aug 2010 00:00:00
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