I am trying to arrange my nodes in the form of a tree. For now, I am working off of this example from here. Currently, I am relying on a force directed layout but am trying to modify it such that I can obtain a tree with predetermined number of levels i.e. if a node belongs to a particular "Layer" it should belong to the same area as other nodes in the layer.
I have tried to explain more in the picture below but does anyone have any suggestions for this? Are there any predetermined algorithms inside d3
that do this or can be tweaked to achieve this?
D3's force layout uses a physics based simulator for positioning visual elements. Forces can be set up between elements, for example: all elements can be configured to repel one another. elements can be attracted to center(s) of gravity. linked elements can be set a fixed distance apart (e.g. for network visualisation)
In the update() function, links = d3. layout. tree(). links(nodes); is 'selecting' the nodes in the tree and their specified links in the JSON file.
A d3. hierarchy is a nested data structure representing a tree: each node has one parent node (node. parent), except for the root; likewise, each node has one or more child nodes (node. children), except for the leaves.
Tree layout is primarily designed for pure trees. It can also be used for non-trees, that is, for cyclic graphs. In this case, the algorithm computes and uses a spanning tree of the graph, ignoring all links that do not belong to the spanning tree. Directed and undirected trees.
Your diagram looks nearly identical to this example which uses a custom gravity force based on the depth. There's another example using a custom force which attracts to the parent node. These are both from my talk on force layouts.
Of course, force layouts are only one option—and as @nrabinowitz said there are many more hierarchy layouts. You can find more interactive hierarchy examples in my SVG Open talk.
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