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I can do this in Code Igniter:
$this->db->select(); $this->from->('node'); if ($published == true) { $this->db->where('published', 'true'); } if (isset($year)) { $this->db->where('year >', $year); } $this->db->get(); How can this code be translated so that it works in Laravel?
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When you are handling more data, it is better to use Laravel's DB facade query builder than Laravel's Eloquent ORM. From performance tests, inserting 1000 rows in a simple table takes Eloquent 1.2 seconds whereas the DB facade takes only 800 milliseconds.
Introduction. Laravel's database query builder provides a convenient, fluent interface to creating and running database queries. It can be used to perform most database operations in your application and works perfectly with all of Laravel's supported database systems.
Laravel multiple where conditions - [OR]: What if you want to use OR condition in your query? You will have to use orWhere() condition for addition query. Note: First query cannot start with orWhere(). It has to be regular where().
The Fluent Query Builder is Laravel's powerful fluent interface for building SQL queries and working with your database. All queries use prepared statements and are protected against SQL injection. You can begin a fluent query using the table method on the DB class.
In Fluent you can do:
$query = DB::table('node'); if ($published == true) $query->where('published', '=', 1); if (isset($year)) $query->where('year', '>', $year); $result = $query->get(); If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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