I want to know how can I form a 2D array using double pointers?
Suppose my array declaration is:
char array[100][100];
How can I get a double pointer which has the same allocation and properties?
To create a char array using malloc
which can be accessed as a 2D array using a[x][y]
and with the data contiguous in memory, one could do:
/* NOTE: only mildly tested. */
char** allocate2Dchar(int count_x, int count_y) {
int i;
# allocate space for actual data
char *data = malloc(sizeof(char) * count_x * count_y);
# create array or pointers to first elem in each 2D row
char **ptr_array = malloc(sizeof(char*) * count_x);
for (i = 0; i < count_x; i++) {
ptr_array[i] = data + (i*count_y);
}
return ptr_array;
}
Note that the returned ptr_array
is a pointer to the array of row pointers. The address of the actual data can be referenced using ptr_array[0]
(first col of first row would be the beginning of the data).
For deallocation, a normal free()
on ptr_array
would be insufficient as the data array itself will still be kicking about.
/* free data array first, then pointer to rows */
void free2Dchar(char** ptr_array) {
if (!ptr_array) return;
if (ptr_array[0]) free(ptr_array[0]);
free(ptr_array);
}
Example usage:
#define ROWS 9
#define COLS 9
int main(int argc, char** argv) {
int i,j, counter = 0;
char **a2d = allocate2Dchar(ROWS, COLS);
/* assign values */
for (i = 0; i < ROWS; i++) {
for (j = 0; j < COLS; j++) {
a2d[i][j] = (char)(33 + counter++);
}
}
/* print */
for (i = 0; i < ROWS; i++) {
for (j = 0; j < COLS; j++) {
printf("%c ", a2d[i][j]);
}
printf("\n");
}
free2Dchar(a2d);
return 0;
}
The above code in action:
[me@home]$ gcc -Wall -pedantic main.c
[me@home]$ ./a.out
! " # $ % & ' ( )
* + , - . / 0 1 2
3 4 5 6 7 8 9 : ;
< = > ? @ A B C D
E F G H I J K L M
N O P Q R S T U V
W X Y Z [ \ ] ^ _
` a b c d e f g h
i j k l m n o p q
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