I'm trying to get buttons to appear when hovering over an image. The following works:
jQuery('.show-image').mouseenter(function() {
jQuery('.the-buttons').animate({
opacity: 1
}, 1500);
}).mouseout(function() {
jQuery('.the-buttons').animate({
opacity: 0
}, 1500);
});
However, when moving from the image to the button (which is over the image), the mouseout/mouseenter is triggered, so the buttons fade out then fade back in (the buttons have the same class as the image, otherwise they just stay faded out). How can I prevent this from triggering? I've also tried the above code using jQuery's hover; same results. Here's a detail of the image showing the button with opacity 1 (because I'm over the image):
http://i.stack.imgur.com/egeVq.png
Thanks in advance for any suggestions.
The best way to swap images on hover is to place both images in the same container, with the "rollover" image transparent by default. When the user hovers over the container, the "rollover" image becomes opaque.
preventDefault() within ontouchstart or ontouchend. It appears to stop the hover effect when the button is touched, but it also stops the button click animation and prevents the onclick function from being called when the button is touched, so you have to call those manually in the ontouchstart or ontouchend handler.
Answer: Use the CSS background-image property You can simply use the CSS background-image property in combination with the :hover pseudo-class to replace or change the image on mouseover.
The simplest solution is to put the two in the same parent div
and give the parent div
the show-image
class.
I like to use .hover()
to save a few key strokes. (alll hover does is implement .mouseenter()
and .mouseleave()
, but you don't have to type them out)
Additionally it's very imporant to fade $(this).find(".the-buttons")
so that you only change the button in the hovered over div
otherwise you would change all of the .the-buttons
on the entire page! .find()
just looks for descendants.
Finally, .animate()
will work, but why not just use .fadeIn()
and .fadeOut()
?
JS:
jQuery(function() { // <== Doc ready
jQuery(".the-buttons").hide(); // Initially hide all buttons
jQuery('.show-image').hover(function() {
jQuery(this).find('.the-buttons').fadeIn(1500); // use .find() !
}, function() {
jQuery(this).find('.the-buttons').fadeOut(1500); // use .find() !
});
});
HTML: - Something like this
<div class="show-image">
<img src="http://i.stack.imgur.com/egeVq.png" />
<input class="the-buttons" type="button" value=" Click " />
</div>
CSS: - Something like this. Yours will likely be different.
div {
position: relative;
float:left;
margin:5px;}
div input {
position:absolute;
top:0;
left:0; }
Put the image and the button in the same div, then put the mouseover/mouseout events on the div. Than whether your mouse is over either the button or the image, it will still be over the div.
Also I am not sure if mouseenter(...).mouseout(...)
will work. I always use hover(..., ...)
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