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When I run the code
hist(1:5)
or
hist(c(1,2,3,4,5))
The generated histogram shows that the first number "1" has frequency of 2 when there is only one "1" in the array.
I also tried
hist(c(1,2,3,7,7,7,9))
but it still shows that the first bar is twice times higher than the second one
However when I run
hist(c(1:10))
The frequency height of every bars are equal
I'm pretty new to statistics and R so I don't know what is the reason behind this. I hope somebody can help me clarify why is this happening. Thank you
789
We can add density line to a histogram by adding another geom_() function; geom_density(). This will convert the frequency histogram into density histogram and add the density line to it. In this example we have added density lien with geom_density() function and specify the color of line as an argument to it.
To create a histogram for uniform data in R, we can simply use hist function but the bars size may vary even if the frequency is same.
To change the number of bins in the histogram in Base R Language, we use the breaks argument of the hist() function. The breaks argument of the hist function to increase or decrease the width of our bars by fixing the number of bars, cells, or bins the whole histogram will be divided into.
Uniform. A histogram is described as “uniform” if every value in a dataset occurs roughly the same number of times. This type of histogram often looks like a rectangle with no clear peaks.
Taking your first example, hist(1:5), you have five numbers, which get put into four bins. So two of those five get lumped into one.
The histogram has breaks at 2, 3, 4, and 5, so you can reasonably infer that the definition of hist for where a number is plotted, is:
#pseudocode
if (i <= break) { # plot in bin }
You can specify the breaks manually to solve this:
hist(1:5, breaks=0:5)
126
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