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Hibernate, how to count with condition

Tags:

hibernate

hql

I am using oracle and hibernate for mapping. I want to count with a condition in count() function. my code is:

select count(case when st.averageMark < su.gradePass then 1 else 0 end)
from Study st join st.subject su
 where st.acaYear in (2009)
  and st.semester = 4
  and su.idSeq = 1330
group by st.acaYear

the code return me nothing. I used sum instead of count it returned a result but it is wrong, the result is bigger than I suppose it to be.

thank in advance.

like image 480
Nathanphan Avatar asked Mar 14 '11 06:03

Nathanphan


2 Answers

I just solved the problem with the following code.

select sum(case when st.averageMark >= su.gradePass then 1 else 0 end) as pass,
       sum(case when  st.averageMark < su.gradePass then 1 else 0 end) as fail
from Study st join st.subject su
where st.acaYear in (2009) and st.semester = 4 and su.idSeq = 1330
group by st.acaYear
like image 141
Nathanphan Avatar answered Oct 03 '22 23:10

Nathanphan


Combining Nathanphan's answer and M. A. Khomeni's comment,

CASE is not supported in COUNT()

So we need to use SUM() instead of COUNT()

For Example:

COUNT(CASE WHEN st.averageMark < su.gradePass THEN 1 ELSE 0 END)

Should be written as

SUM(CASE WHEN st.averageMark < su.gradePass THEN 1 ELSE 0 END)
like image 39
Emdadul Sawon Avatar answered Oct 04 '22 00:10

Emdadul Sawon