I'm using hibernate 4 and xml based mapping. Here is the exception I'm getting
Caused by: org.hibernate.MappingException: Unable to instantiate custom type: org.hibernate.type.EnumType
at org.hibernate.type.TypeFactory.custom(TypeFactory.java:193)
at org.hibernate.type.TypeFactory.custom(TypeFactory.java:179)
at org.hibernate.type.TypeFactory.byClass(TypeFactory.java:103)
at org.hibernate.type.TypeResolver.heuristicType(TypeResolver.java:130)
at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:307)
at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:294)
at org.hibernate.mapping.Property.isValid(Property.java:238)
at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:469)
at org.hibernate.mapping.RootClass.validate(RootClass.java:270)
at org.hibernate.cfg.Configuration.validate(Configuration.java:1294)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1742)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1788)
at org.springframework.orm.hibernate4.LocalSessionFactoryBuilder.buildSessionFactory(LocalSessionFactoryBuilder.java:189)
at org.springframework.orm.hibernate4.LocalSessionFactoryBean.buildSessionFactory(LocalSessionFactoryBean.java:350)
at org.springframework.orm.hibernate4.LocalSessionFactoryBean.afterPropertiesSet(LocalSessionFactoryBean.java:335)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory$6.run(AbstractAutowireCapableBeanFactory.java:1504)
at java.security.AccessController.doPrivileged(Native Method)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1502)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1452)
... 35 more
Caused by: java.lang.NullPointerException
at org.hibernate.type.EnumType.setParameterValues(EnumType.java:153)
at org.hibernate.type.TypeFactory.injectParameters(TypeFactory.java:131)
at org.hibernate.type.TypeFactory.custom(TypeFactory.java:189)
... 53 more
And here is the enum mapping that I'm using
<property name="coachingStatus" column="status" update="true" insert="true" index="true">
<type name="org.hibernate.type.EnumType">
<param name="enumClass">com.tutorial.enums.CoachingStatus</param>
<param name="type">12</param>
</type>
</property>
And here is the enum:
public enum CoachingStatus {
ACTIVE, BLOCKED, PENDING, EXPIRED
}
here is the entity
public class Coaching implements Serializable {
private Integer id;
private String name;
private Long locationId;
private Integer organisationId;
private Long ownerId;
private Date createdOn;
private Date modifiedOn;
private CoachingStatus coachingStatus;
private Long createdBy;
private Long modifiedBy;
private String email;
private String logo;
private String about;
private String phone;
... //getters and setters
}
I checked out tutorial from here - here but I'm getting above error. Need help with this.
I had same problem and it looks like the solution is to add another parameter. That way it won't try to persist it as ordinal but as string so I guess that string works better with VARCHAR type.
<property name="coachingStatus" column="status" update="true" insert="true" index="true">
<type name="org.hibernate.type.EnumType">
<param name="enumClass">com.tutorial.enums.CoachingStatus</param>
<param name="type">12</param>
<param name="useNamed">true</param>
</type>
</property>
by setting useNamed
to true
hibernate will store enum by using it's name so your data will not break if you change order in your enum type.
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