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Heavy tail distribution - Weibull [closed]

I know that the Weibull distribution exhibits subexponential heavy-tailed behavior when the shape parameter is < 1. I need to demonstrate this using the limit definition of a heavy tailed distribution:

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How do I incorporate the cumulative distribution function (CDF) or any other equation characteristic of the Weibull distribution to prove that this limit holds?

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ejf071189 Avatar asked Sep 01 '25 22:09

ejf071189


1 Answers

The CDF of the Weibull distribution is 1 - exp(-(x/lambda)^k) = P(X <= x).

So

P(X > x) = 1 - CDF = exp(-(x/lambda)^k),

and

lim exp(lambda * x) * P(X > x) = lim exp(lambda x) * exp( - (x/lambda)^k)
                               = lim exp(lambda x - x^k/lambda^k)

Since k<1, and x is large, and lambda>0, lambda x grows large faster than x^k/lambda^k (the monomial with the greater exponent wins). In other words, the lambda x term dominates the x^k/lambda^k term. So lambda x - x^k/lambda^k is large and positive.

Thus, the limit goes to infinity.

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unutbu Avatar answered Sep 04 '25 10:09

unutbu