I'm trying to create a Hash-table by using an array on linked-nodes (making a linked list). But I'm having difficulties inserting a value into the Hash-table. When I run it, I get this:
http://gyazo.com/3a28a70e66b3ea34e08223e5948f49c0.png
Here is my code:
#include <iostream>
using namespace std;
class Node {
public:
int num;
Node * next;
};
class intHashTable {
private:
int size;
Node ** table;
public:
intHashTable(int size); // construct a new hash table with size elements
~intHashTable(); // delete the memory for all internal components
void insert(int num); // insert num into the hash table, no effect
// if num is already in table
void remove(int num); // remove num from the hash table, no effect if not in table
int lookup(int num); // return 1 if num is already in table, 0 otherwise
void print(void); // print the elements of the hash table to the screen
};
// construct a new hash table with nelements elements
intHashTable::intHashTable(int nelements)
{
size = nelements;
table = new Node*[size];
for ( int i = 0; i < size; i++ ) {
table[i] = NULL;
}
}
intHashTable::~intHashTable()
{
for(int i=0; i<size; i++)
{
Node* temp = table[i];
while(temp != NULL)
{
Node* next = temp->next;
delete temp;
temp = next;
}
}
size = 0;
delete[] table;
}
void intHashTable::insert(int num){
int location = ((unsigned)num) % size;
Node *runner = table[location];
if(runner == NULL ){
runner->num = num;
}else{
while(runner != NULL ){
runner = runner->next;
}
runner->num = num;
}
}
int main(){
intHashTable a (10);
a.insert(2);
return 0;
}
A hash table is just an array of linked lists. Each linked list holds all the items in the table that share the same hash code. Initially, all the lists are empty (represented as null in the array).
If you have one or a few large lists, then a hash table is likely to out-perform a sorted list. Why might lookups be faster with a sorted list? Well, it's clear that it's faster than a linked list, with the latter's O(N) lookup time.
A Hash Table in C/C++ (Associative array) is a data structure that maps keys to values. This uses a hash function to compute indexes for a key. Based on the Hash Table index, we can store the value at the appropriate location.
2. What is the advantage of the hash table over a linked list? Explanation: Hash table is a data structure that has an advantage that it allows fast access of elements. But linked list is easier to implement as compared to the hash table.
After construction of intHashTable
, all the elements of table
are still NULL
. However, in the function insert
, one element is dereferenced:
Node *runner = table[location];
runner = runner->next;
This makes the program crash, because it is illegal to dereference a null pointer.
the logic here is wrong
int location = ((unsigned)num) % size;
Node *runner = table[location];
if(runner == NULL ) // if null u dereference it!
{
runner->num = num;
}
else
{
while(runner != NULL ) { // u loop until null
runner = runner->next;
}
runner->num = num; // once u reach null u dereference it!
}
i would suggest instead:
first a ctor
for your Node
class Node {
public:
int num;
Node * next;
Node( int _n ) : num(_n), next(NULL) { }
};
and then
if ( runner != NULL )
{
while ( runner->next != NULL )
{
runner = runner->next;
}
runner->next = new Node( num );
}
else
{
table[location] = new Node( num );
}
This code certainly won't work:
if(runner == NULL ){
runner->num = num;
If runner is NULL, then you should never dereference it (using * or -> on it).
Node *runner = table[location];
runner = runner->next;
if(runner == NULL )
You never verified whether table[location]
is null. But during construction of your hashtable, there are no nodes inside the node table (you set yourself every entry to null).
The problem with your code is that you never think about allocating your node. You should be doing
Node* toInsert = new Node;
toInsert->next= NULL;
toInsert->num = num;
if(table[location]==NULL){
table[location] = toInsert;
}
else{
Node *runner = table[location];
while(runner->next != NULL){
runner = runner->next;
}
runner->next = toInsert;
}
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