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Guidance on Algorithmic Thinking (4 fours equation)

I recently saw a logic/math problem called 4 Fours where you need to use 4 fours and a range of operators to create equations that equal to all the integers 0 to N.

How would you go about writing an elegant algorithm to come up with say the first 100...

I started by creating base calculations like 4-4, 4+4, 4x4, 4/4, 4!, Sqrt 4 and made these values integers.

However, I realized that this was going to be a brute force method testing the combinations to see if they equal, 0 then 1, then 2, then 3 etc...

I then thought of finding all possible combinations of the above values, checking that the result was less than 100 and filling an array and then sorting it...again inefficient because it may find 1000s of numbers over 100

Any help on how to approach a problem like this would be helpful...not actual code...but how to think through this problem

Thanks!!

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Omar Avatar asked Jun 02 '15 11:06

Omar


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What is the four 4s problem?

The goal of the four fours problem is to find a mathematical expression for every integer from 0 to some maximum positive integer, using only common mathematical symbols and exactly four fours (no other digits are allowed). For example, zero is 44-44, one is 44/44, 2 is 4/4+4/4, 3 is (4+4+4)/4, and so on.


1 Answers

This is an interesting problem. There are a couple of different things going on here. One issue is how to describe the sequence of operations and operands that go into an arithmetic expression. Using parentheses to establish order of operations is quite messy, so instead I suggest thinking of an expression as a stack of operations and operands, like - 4 4 for 4-4, + 4 * 4 4 for (4*4)+4, * 4 + 4 4 for (4+4)*4, etc. It's like Reverse Polish Notation on an HP calculator. Then you don't have to worry about parentheses, having the data structure for expressions will help below when we build up larger and larger expressions.

Now we turn to the algorithm for building expressions. Dynamic programming doesn't work in this situation, in my opinion, because (for example) to construct some numbers in the range from 0 to 100 you might have to go outside of that range temporarily.

A better way to conceptualize the problem, I think, is as breadth first search (BFS) on a graph. Technically, the graph would be infinite (all positive integers, or all integers, or all rational numbers, depending on how elaborate you want to get) but at any time you'd only have a finite portion of the graph. A sparse graph data structure would be appropriate.

Each node (number) on the graph would have a weight associated with it, the minimum number of 4's needed to reach that node, and also the expression which achieves that result. Initially, you would start with just the node (4), with the number 1 associated with it (it takes one 4 to make 4) and the simple expression "4". You can also throw in (44) with weight 2, (444) with weight 3, and (4444) with weight 4.

To build up larger expressions, apply all the different operations you have to those initial node. For example, unary negation, factorial, square root; binary operations like * 4 at the bottom of your stack for multiply by 4, + 4, - 4, / 4, ^ 4 for exponentiation, and also + 44, etc. The weight of an operation is the number of 4s required for that operation; unary operations would have weight 0, + 4 would have weight 1, * 44 would have weight 2, etc. You would add the weight of the operation to the weight of the node on which it operates to get a new weight, so for example + 4 acting on node (44) with weight 2 and expression "44" would result in a new node (48) with weight 3 and expression "+ 4 44". If the result for 48 has better weight than the existing result for 48, substitute that new node for (48).

You will have to use some sense when applying functions. factorial(4444) would be a very large number; it would be wise to set a domain for your factorial function which would prevent the result from getting too big or going out of bounds. The same with functions like / 4; if you don't want to deal with fractions, say that non-multiples of 4 are outside of the domain of / 4 and don't apply the operator in that case.

The resulting algorithm is very much like Dijkstra's algorithm for calculating distance in a graph, though not exactly the same.

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Edward Doolittle Avatar answered Oct 05 '22 02:10

Edward Doolittle