I have a numeric vector like this x <- c(1, 23, 7, 10, 9, 2, 4) and I want to group the elements from left to right with the constrain that each group sum must not exceed 25. Thus, here the first group is c(1, 23), the second is c(7, 10) and the last c(9, 2, 4). the expected output is a dataframe with a second column containing the groups:
data.frame(x= c(1, 23, 7, 10, 9, 2, 4), group= c(1, 1, 2, 2, 3, 3, 3))
I have tried different things with cumsum but am not able to kind of dynamically restart cumsum for the new group once the limit sum of 25 for the last group is reached.
I think cpp function is the fastest way:
library(Rcpp)
cppFunction(
"IntegerVector GroupBySum(const NumericVector& x, const double& max_sum = 25)
{
double sum = 0;
int cnt = 0;
int period = 1;
IntegerVector res(x.size());
for (int i = 0; i < x.size(); ++i)
{
++cnt;
sum += x[i];
if (sum > max_sum)
{
sum = x[i];
if (cnt > 1)
++period;
cnt = 1;
}
res[i] = period;
}
return res;
}"
)
GroupBySum(c(1, 23, 7, 10, 9, 2, 4), 25)
We can try this as a programming practice if you like :)
f1 <- function(x) {
group <- c()
while (length(x)) {
idx <- cumsum(x) <= 25
x <- x[!idx]
group <- c(group, rep(max(group, 0) + 1, sum(idx)))
}
group
}
or
f2 <- function(x) {
group <- c()
g <- 0
while (length(x)) {
cnt <- s <- 0
for (i in seq_along(x)) {
s <- s + x[i]
if (s <= 25) {
cnt <- cnt + 1
} else {
break
}
}
g <- g + 1
group <- c(group, rep(g, cnt))
x <- x[-(1:cnt)]
}
group
}
or
f3 <- function(x) {
s <- cumsum(x)
r <- c()
grp <- 1
while (length(s)) {
idx <- (s <= 25)
r <- c(r, rep(grp, sum(idx)))
grp <- grp + 1
s <- s[!idx] - tail(s[idx], 1)
}
r
}
which gives
[1] 1 1 2 2 3 3 3
and benchmarking among them looks like
set.seed(1)
set.seed(1)
x <- runif(1e3, 0, 25)
bm <- microbenchmark(
f1(x),
f2(x),
f3(x),
check = "equivalent"
)
autoplot(bm)

Another option is using recursion (based on f1())
f <- function(x, res = c()) {
if (!length(x)) {
return(res)
}
idx <- cumsum(x) <= 25
Recall(x[!idx], res = c(res, list(x[idx])))
}
and you will see
> f(x)
[[1]]
[1] 1 23
[[2]]
[1] 7 10
[[3]]
[1] 9 2 4
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