I have list of items, for example: { i1, i2, i3, i4, i5, i6, i7 }
.
I want to get a list, where every item is a pair of items from source list: { {i1, i2}, {i3, i4}, {i5, i6}, {i7} }
.i7
is a single item in pair because there is no item i8
.
Is it possible to do with LINQ?
Well, you could do:
var pairs = sequence.Select((value, index) => new { value, index } )
.GroupBy(x => x.index / 2, x => x.value)
The result is an IGrouping<int, T>
with a key of 0, 1, 2 etc and the contents of each group being one or two items.
However, I'd possibly write a custom extension method:
public static IEnumerable<Tuple<T, T>> PairUp<T>(this IEnumerable<T> source)
{
using (var iterator = source.GetEnumerator())
{
while (iterator.MoveNext())
{
var first = iterator.Current;
var second = iterator.MoveNext() ? iterator.Current : default(T);
yield return Tuple.Create(first, second);
}
}
}
This will yield a sequence of tuples - the downside here is that the final tuple will have the default value for T
as the "second" item if the sequence has an odd number of items. For reference types where the sequence only consists of non-null values, that's okay, but for some sequences it wouldn't help.
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