Given the following table:
ID State Date 12 1 2009-07-16 10:00 45 2 2009-07-16 13:00 67 2 2009-07-16 14:40 77 1 2009-07-16 15:00 89 1 2009-07-16 15:30 99 1 2009-07-16 16:00
Question:
How can i GROUP by the field "State", while still maintaining the borders between the state changes?
SELECT MIN(ID) AS ID, State, MIN(Date) AS Date, COUNT(ID) AS Count
FROM table GROUP BY State
results in the following:
ID State Date Count 12 1 2009-07-16 10:00 4 45 2 2009-07-16 13:00 2
but this is the desired output:
ID State Date Count 12 1 2009-07-16 10:00 1 45 2 2009-07-16 13:00 2 77 1 2009-07-16 15:00 3
The Group By statement is used to group together any rows of a column with the same value stored in them, based on a function specified in the statement. Generally, these functions are one of the aggregate functions such as MAX() and SUM(). This statement is used with the SELECT command in SQL.
We can use the group by multiple-column technique to group multiple records into a single record. All the records with the same values for the respective columns mentioned in the grouping criteria can be grouped as a single column using the group by multiple-column technique.
Yes, it is possible to use MySQL GROUP BY clause with multiple columns just as we can use MySQL DISTINCT clause.
You can use a SELECT command with a GROUP BY clause to group all rows that have identical values in a specified column or combination of columns, into a single row.
SELECT MIN(id) AS id, MIN(ts) AS ts, MIN(state) AS state, COUNT(*) cnt
FROM (
SELECT @r := @r + (@state != state) AS gn,
@state := state AS sn,
s.*
FROM (
SELECT @r := 0,
@state := 0
) vars,
t_state s
ORDER BY
ts
) q
GROUP BY
gn
Table creation scripts for testing:
CREATE TABLE t_state (id INT NOT NULL PRIMARY KEY, state INT NOT NULL, ts DATETIME NOT NULL);
INSERT
INTO t_state
VALUES
(12, 1, '2009-07-16 10:00'),
(45, 2, '2009-07-16 13:00'),
(67, 2, '2009-07-16 14:40'),
(77, 1, '2009-07-16 15:00'),
(89, 1, '2009-07-16 15:30'),
(99, 1, '2009-07-16 16:00');
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