In Java 8:
Map<String, List<Student>> studlistGrouped =
studlist.stream().collect(Collectors.groupingBy(w -> w.stud_location));
This will add the students object to the HashMap
with locationID
as key.
HashMap<Integer, List<Student>> hashMap = new HashMap<Integer, List<Student>>();
Iterate over this code and add students to the HashMap
:
if (!hashMap.containsKey(locationId)) {
List<Student> list = new ArrayList<Student>();
list.add(student);
hashMap.put(locationId, list);
} else {
hashMap.get(locationId).add(student);
}
If you want all the student with particular location details then you can use this:
hashMap.get(locationId);
which will get you all the students with the same the location ID.
Map<String, List<Student>> map = new HashMap<String, List<Student>>();
for (Student student : studlist) {
String key = student.stud_location;
if(map.containsKey(key)){
List<Student> list = map.get(key);
list.add(student);
}else{
List<Student> list = new ArrayList<Student>();
list.add(student);
map.put(key, list);
}
}
Using Java 8
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;
import java.util.stream.Stream;
class Student {
String stud_id;
String stud_name;
String stud_location;
public String getStud_id() {
return stud_id;
}
public String getStud_name() {
return stud_name;
}
public String getStud_location() {
return stud_location;
}
Student(String sid, String sname, String slocation) {
this.stud_id = sid;
this.stud_name = sname;
this.stud_location = slocation;
}
}
class Temp
{
public static void main(String args[])
{
Stream<Student> studs =
Stream.of(new Student("1726", "John", "New York"),
new Student("4321", "Max", "California"),
new Student("2234", "Max", "Los Angeles"),
new Student("7765", "Sam", "California"));
Map<String, Map<Object, List<Student>>> map= studs.collect(Collectors.groupingBy(Student::getStud_name,Collectors.groupingBy(Student::getStud_location)));
System.out.println(map);//print by name and then location
}
}
The result will be:
{
Max={
Los Angeles=[Student@214c265e],
California=[Student@448139f0]
},
John={
New York=[Student@7cca494b]
},
Sam={
California=[Student@7ba4f24f]
}
}
Probably it's late but I like to share an improved idea to this problem. This is basically the same of @Vitalii Fedorenko's answer but more handly to play around.
You can just use the Collectors.groupingBy()
by passing the grouping logic as function parameter and you will get the splitted list with the key parameter mapping. Note that using Optional
is used to avoid the unwanted NPE when the provided list is null
public static <E, K> Map<K, List<E>> groupBy(List<E> list, Function<E, K> keyFunction) {
return Optional.ofNullable(list)
.orElseGet(ArrayList::new)
.stream()
.collect(Collectors.groupingBy(keyFunction));
}
Now you can groupBy anything with this. For the use case here in the question
Map<String, List<Student>> map = groupBy(studlist, Student::getLocation);
Maybe you would like to look into this also Guide to Java 8 groupingBy Collector
You can use the following:
Map<String, List<Student>> groupedStudents = new HashMap<String, List<Student>>();
for (Student student: studlist) {
String key = student.stud_location;
if (groupedStudents.get(key) == null) {
groupedStudents.put(key, new ArrayList<Student>());
}
groupedStudents.get(key).add(student);
}
Set<String> groupedStudentsKeySet = groupedCustomer.keySet();
for (String location: groupedStudentsKeySet) {
List<Student> stdnts = groupedStudents.get(location);
for (Student student : stdnts) {
System.out.println("ID : "+student.stud_id+"\t"+"Name : "+student.stud_name+"\t"+"Location : "+student.stud_location);
}
}
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