Grep : get all file that doesn't have a line that matches [closed]

Question

I have a lots of files with multiple lines, and in most case, one of the lines contain a certain pattern. I would like to list every file that does not have a line with this pattern.

Answer 1

Use the "-L" option in order to have file WITHOUT the pattern. Per the man page:

-L, --files-without-match

Suppress normal output; instead print the name of each input file from which no output would normally have been printed. The scanning will stop on the first match.

Answer 2

Grep returns 0/1 to indicate if there was a match, so you can do something like this:

for f in *.txt; do     if ! grep -q "some expression" $f; then         echo $f     fi done 

EDIT: You can also use the -L option:

grep -L "some expression" *