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grep all characters including newline

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regex

grep

I'm parsing an XML file with

"lalala it's a Sunday {{ Some words here, maybe
a new line }} oh boy"

How would I use grep to get everything within "{{" and "}}" given that the grep . character doesn't recognize newlines?

Currently I have

grep '{{.*}}'

but it only works on things that are on the same line.

like image 694
Rio Avatar asked Feb 20 '11 17:02

Rio


3 Answers

One option is to remove the newline and then grep, as in:

 cat myfile | tr -d '\n' | grep {{.*}}

But if you say this is an XML file, why not use an XML parser that takes advantage of the file's inherent structure rather than just regexp?

EDIT

Grep regexp are greedy, you can use perl regexp:

cat myfile | tr -d '\n' | perl -pe 's/.*?({{.*?}})/\1\n/g' | grep {{

This should output one match per line. If you have nested {{ then this will get even more complicated.

like image 185
Jesse Cohen Avatar answered Oct 19 '22 15:10

Jesse Cohen


This is the way i solved that problem

   grep '{{[\s\S]*}}'
like image 42
Yuri Barbashov Avatar answered Oct 19 '22 15:10

Yuri Barbashov


You can use alternation between mutually exclusive character sets to match truly any character. For example, this command:

grep -E "\{\{([[:digit:]]|[^[:digit:]])+\}\}"

...will match anything (greedily) between the first {{ and last }}.

But as @JesseCohen states, you really, really, really should be parsing XML with an XML parser, not regexps.

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Phrogz Avatar answered Oct 19 '22 17:10

Phrogz