When I call mFirebaseAuth.signOut()
or mFirebaseUser.delete()
my FirebaseAuth.AuthStateListener()
works correctly and returns null
as FirebaseUser
instance in onAuthStateChanged
, I refresh UI and show "Sign in with Google" button.
But when I want to log in again, I don't see the dialog with users (I have 2 users on my device, attached the image). The app shows this dialog only in first sign in, after that it uses the same user. If I clear app's data on the settings screen I will be able to see this dialog again.
My question is how to show this dialog after every sign out.
I run this code when press Sign In button:
// in onCreate()
GoogleSignInOptions gso = new GoogleSignInOptions.Builder(GoogleSignInOptions.DEFAULT_SIGN_IN)
.requestIdToken(getString(R.string.default_web_client_id))
.requestEmail()
.build();
mGoogleApiClient = new GoogleApiClient.Builder(this)
.enableAutoManage(this /* FragmentActivity */, this /* OnConnectionFailedListener */)
.addApi(Auth.GOOGLE_SIGN_IN_API, gso)
.build();
// in OnClickListener
Intent signInIntent = Auth.GoogleSignInApi.getSignInIntent(mGoogleApiClient);
startActivityForResult(signInIntent, FirebaseActivity.REQUEST_SIGN_IN);
In onActivityResult()
, I get an instance of GoogleSignInResult
so everything I need happens after I call startActivityForResult()
.
You can also delete users from the Authentication section of the Firebase console, on the Users page. Important: To delete a user, the user must have signed in recently. See Re-authenticate a user.
If signing in is successful, the developer console will log in our user. We can also click on the Google Signout button to logout from the app. The console will confirm that the logout was successful.
The underlying ID token that authenticates refreshes every hour. So, after an account is deleted, the client will be authenticated for up to one hour. Only until it tries to refresh the ID token will the client become unauthenticated.
To detect if a user is already logged in Firebase with JavaScript, we can call the onAuthStateChanged method. firebase. auth(). onAuthStateChanged((user) => { if (user) { // ... } else { // ... } });
In the Firebase Auth Quickstart sample code, the sign-out for Google provider includes these steps. Are you calling GoogleSignInClient.signOut()
when you sign-out?
private void signOut() {
// Firebase sign out
mAuth.signOut();
// Google sign out
mGoogleSignInClient.signOut().addOnCompleteListener(this,
new OnCompleteListener<Void>() {
@Override
public void onComplete(@NonNull Task<Void> task) {
updateUI(null);
}
});
}
Another option is to use the FirebaseUI library. It simplifies sign in and sign out operations in a sense that it will do all the heavy lifting for you.
Kotlin
AuthUI.getInstance().signOut(this).addOnCompleteListener {
// do something here
}
Java
AuthUI.getInstance()
.signOut(ActivityMainOld.this)
.addOnCompleteListener(new OnCompleteListener<Void>(){
@Override
public void onComplete(@NonNull Task<Void> task) {
// do something here
}
});
Hope this helps
I was confused since all of the solutions required having a reference to the GoogleSignInClient
, but it is actually not required for you to hold a reference to it, you can simply create a new instance and call signOut()
on it.
GoogleSignIn.getClient(
getContext(),
new GoogleSignInOptions.Builder(GoogleSignInOptions.DEFAULT_SIGN_IN).build()
).signOut();
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