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Google custom search next page

I have the following code, and i don't know how to print the links of the next page, how to go to the next pages?

#!/usr/bin/python2.4
# -*- coding: utf-8 -*-


import pprint

from apiclient.discovery import build


def main():

    service = build("customsearch", "v1",
                 developerKey="")

    res = service.cse().list(
         q='lectures',
         cx='013036536707430787589:_pqjad5hr1a',
         num=10, #Valid values are integers between 1 and 10, inclusive.
    ).execute() 

    for value in res:
        #print value
        if 'items' in value:
            for results in res[value]:
                print results['formattedUrl'] 

if __name__ == '__main__':
  main()
like image 995
badc0re Avatar asked Jul 19 '12 06:07

badc0re


3 Answers

# define the pages you want to scrape
max_page = 3

def google_search(service, query_keywords, api_key, cse_id):
    res = service.cse().list(q=query_keywords, cx=cse_id).execute()
    return res

def google_next_page(service, query_keywords, api_key, cse_id, res, page, max_page, url_items):
    next_res = service.cse().list(q=query_keywords, cx=cse_id, num=10, start=res['queries']['nextPage'][0]['startIndex'],).execute()
    for item in next_res['items']:
        url_items.append(item)
    page += 1
    
    if page == max_page:
        return url_items

    return google_next_page(service, query_keywords, api_key, cse_id, next_res, page, max_page, url_items)
    
like image 124
Newt Avatar answered Oct 18 '22 06:10

Newt


The response object contains a 'nextPage' dictionary. You can use this to determine the start index of the next request. Like so:

res = service.cse().list(
     q='lectures',
     cx='013036536707430787589:_pqjad5hr1a',
     num=10, #Valid values are integers between 1 and 10, inclusive.
).execute() 

next_response = service.cse().list(
     q='lectures',
     cx='013036536707430787589:_pqjad5hr1a',
     num=10,
     start=res['queries']['nextPage'][0]['startIndex'],
).execute() 
like image 14
aychedee Avatar answered Oct 18 '22 06:10

aychedee


My proposition is to add next parameter. In current software you have q, cx and num. You could try add start=10 and then execute the code.

res = service.cse().list(
    q='lectures',
    cx='013036536707430787589:_pqjad5hr1a',
    num=10,
    start=10,
).execute()

First result page URL doesn't have start parameter. Second page has URL which contains start=10 parameter. Third page has URL which contains start=20 ...

Good luck

like image 8
Pawel Avatar answered Oct 18 '22 07:10

Pawel