I am struggling to understand exactly what is happening when you return a new object from a function in go.
I have this
func createPointerToInt() *int {
i := new(int)
fmt.Println(&i);
return i;
}
func main() {
i := createPointerToInt();
fmt.Println(&i);
}
The values printed returned are
0x1040a128
0x1040a120
I would expect these two values to be the same. I do not understand why there is an 8 byte difference.
In what I see as the equivalent C code:
int* createPointerToInt() {
int* i = new int;
printf("%#08x\n", i);
return i;
}
int main() {
int* r = createPointerToInt();
printf("%#08x\n", r);
return 0;
}
The address returned is the same:
0x8218008
0x8218008
Am I missing something blindingly obvious here? Any clarification would be greatly appreciated!
You are printing the address of the pointer here fmt.Println(&i);
. Try this:
func main() {
i := createPointerToInt();
fmt.Println(i); //--> Remove the ampersand
}
i
is the pointer returned from createPointerToInt
- while &i
is the address of the pointer you are trying to print. Note in your C sample you are printing it correctly:
printf("%#08x\n", r);
^No ampersand here
Change &i
to i
. You are printing address of i while you should print the value of i.
func createPointerToInt() *int {
i := new(int)
fmt.Println(i);
return i;
}
func main() {
i := createPointerToInt();
fmt.Println(i);
}
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