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The golang blog states :
"A slice can also be formed by "slicing" an existing slice or array. Slicing is done by specifying a half-open range with two indices separated by a colon. For example, the expression b[1:4] creates a slice including elements 1 through 3 of b (the indices of the resulting slice will be 0 through 2)."
Can someone please explain to me the logic in the above. IE. Why doesn't b[1:4] reference elements 1 through 4? Is this consistent with other array referencing?
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To answer the original question, you can pass a pointer to the array, to pass the array by reference. For example, the following function changes the contents of an array of 3 integers. hence it gives you the error cannot use a (type [100]int) as type *int in argument to f .
In a nutshell, the [:] operator allows you to create a slice from an array, optionally using start and end bounds.
creating a slice using make func make([]T, len, cap) []T can be used to create a slice by passing the type, length and capacity. The capacity parameter is optional and defaults to the length. The make function creates an array and returns a slice reference to it.
Slices in Go and Golang The basic difference between a slice and an array is that a slice is a reference to a contiguous segment of an array. Unlike an array, which is a value-type, slice is a reference type. A slice can be a complete array or a part of an array, indicated by the start and end index.
Indexes point to the "start" of the element. This is shared by all languages using zero-based indexing:
| 0 | first | 1 | second | 2 | third | 3 | fourth | 4 | fifth | 5 |
[0] = ^
[0:1] = ^ --------> ^
[1:4] = ^-------------------------------------> ^
[0:5] = ^ ----------------------------------------------------------> ^
It's also common to support negative indexing, although Go doesn't allow this:
|-6 | |-5 | |-4 | |-3 | |-2 | |-1 |
| 0 | first | 1 | second | 2 | third | 3 | fourth | 4 | fifth | 5 |
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