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Go - Golang openpg - Create Key pair and create signature

I'm currently working on openpgp in combination with golang. I use the following code to generate a new keypair and create a self-signature on the resulting public key:

package main

import (
    "bytes"
    "crypto"
    "time"
    "golang.org/x/crypto/openpgp"
    "golang.org/x/crypto/openpgp/armor"
    "golang.org/x/crypto/openpgp/packet"
    "fmt"
)

//Create ASscii Armor from openpgp.Entity
func PubEntToAsciiArmor(pubEnt *openpgp.Entity) (asciiEntity string) {
    gotWriter := bytes.NewBuffer(nil)
    wr, errEncode := armor.Encode(gotWriter, openpgp.PublicKeyType, nil)
    if errEncode != nil {
        fmt.Println("Encoding Armor ", errEncode.Error())
        return
    }
    errSerial := pubEnt.Serialize(wr)
    if errSerial != nil {
        fmt.Println("Serializing PubKey ", errSerial.Error())
    }
    errClosing := wr.Close()
    if errClosing != nil {
        fmt.Println("Closing writer ", errClosing.Error())
    }
    asciiEntity = gotWriter.String()
    return
}


func main() {

    var entity *openpgp.Entity
    entity, err := openpgp.NewEntity("itis", "test", "[email protected]", nil)
    if err != nil {
        fmt.Println("ERROR")
    }

    usrIdstring := ""
    for _, uIds := range entity.Identities {
        usrIdstring = uIds.Name

    }

    var priKey = entity.PrivateKey
    var sig = new(packet.Signature)    
    //Prepare sign with our configs/////IS IT A MUST ??
    sig.Hash = crypto.SHA1
    sig.PubKeyAlgo = priKey.PubKeyAlgo
    sig.CreationTime = time.Now()
    dur := new(uint32)
    *dur = uint32(365 * 24 * 60 * 60)
    sig.SigLifetimeSecs = dur //a year
    issuerUint := new(uint64)
    *issuerUint = priKey.KeyId
    sig.IssuerKeyId = issuerUint
    sig.SigType = packet.SigTypeGenericCert


    err = sig.SignKey(entity.PrimaryKey, entity.PrivateKey, nil)
    if err != nil {
        fmt.Println("ERROR")
    }
    err = sig.SignUserId(usrIdstring, entity.PrimaryKey, entity.PrivateKey, nil)
    if err != nil {
        fmt.Println("ERROR")
    }

    entity.SignIdentity(usrIdstring, entity, nil)

    var copy = entity
    var asciiSignedKey = PubEntToAsciiArmor(copy)
    fmt.Println(asciiSignedKey)
}

1.) When I serialize the public key (to get an armored version of it), I get the following error message:

Serializing PubKey openpgp: invalid argument: Signature: need to call Sign, SignUserId or SignKey before Serialize

I thought I just used every possible way to create a signature on that key?

2.) I still receive an output from problem 1, when I upload the key to a keyserver, than the available information are incomplete. Only the key-id and the creation date are listed. All additional information like, self-signature, user-id-string and so on are missing (example: https://pgp.mit.edu/pks/lookup?search=0xbe6ee21e94a73ba5&op=index). What went wrong? Is it related to error 1?

PS: I am new to golang, started today.

like image 686
Thea Queen Avatar asked Feb 10 '23 07:02

Thea Queen


1 Answers

Maybe this will do what you want. Disclaimer: I am not an expert in openpgp; I don't know whether this is correct or not. But it does work with gpg --import.

package main

import (
        "fmt"
        "os"

        "golang.org/x/crypto/openpgp"
        "golang.org/x/crypto/openpgp/armor"
)

func main() {
        var e *openpgp.Entity
        e, err := openpgp.NewEntity("itis", "test", "[email protected]", nil)
        if err != nil {
                fmt.Println(err)
                return
        }

        // Add more identities here if you wish

        // Sign all the identities
        for _, id := range e.Identities {
                err := id.SelfSignature.SignUserId(id.UserId.Id, e.PrimaryKey, e.PrivateKey, nil)
                if err != nil {
                        fmt.Println(err)
                        return
                }
        }

        w, err := armor.Encode(os.Stdout, openpgp.PublicKeyType, nil)
        if err != nil {
                fmt.Println(err)
                return
        }
        defer w.Close()

        e.Serialize(w)
}
like image 72
Matt Avatar answered Feb 13 '23 05:02

Matt