Go - Convert 2 byte array into a uint16 value

Question

If I have a slice of bytes in Go, similar to this:

numBytes := []byte { 0xFF, 0x10 }

How would I convert it to it's uint16 value (0xFF10, 65296)?

Answer 1

To combine two bytes into uint16

x := uint16(numBytes[i])<<8 | uint16(numBytes[i+1])

where i is the starting position of the uint16. So if your array is always only two items it would be x := uint16(numBytes[0])<<8 | uint16(numBytes[1])