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ggplot2 pie and donut chart on same plot

I am trying to replicate this enter image description here with R ggplot. I have exactly the same data:

browsers<-structure(list(browser = structure(c(3L, 3L, 3L, 3L, 2L, 2L,  2L, 1L, 5L, 5L, 4L), .Label = c("Chrome", "Firefox", "MSIE",  "Opera", "Safari"), class = "factor"), version = structure(c(5L,  6L, 7L, 8L, 2L, 3L, 4L, 1L, 10L, 11L, 9L), .Label = c("Chrome 10.0",  "Firefox 3.5", "Firefox 3.6", "Firefox 4.0", "MSIE 6.0", "MSIE 7.0",  "MSIE 8.0", "MSIE 9.0", "Opera 11.x", "Safari 4.0", "Safari 5.0" ), class = "factor"), share = c(10.85, 7.35, 33.06, 2.81, 1.58,  13.12, 5.43, 9.91, 1.42, 4.55, 1.65), ymax = c(10.85, 18.2, 51.26,  54.07, 55.65, 68.77, 74.2, 84.11, 85.53, 90.08, 91.73), ymin = c(0,  10.85, 18.2, 51.26, 54.07, 55.65, 68.77, 74.2, 84.11, 85.53,  90.08)), .Names = c("browser", "version", "share", "ymax", "ymin" ), row.names = c(NA, -11L), class = "data.frame") 

and it looks like this:

> browsers    browser      version  share   ymax   ymin 1     MSIE     MSIE 6.0  10.85  10.85   0.00 2     MSIE     MSIE 7.0   7.35  18.20  10.85 3     MSIE     MSIE 8.0  33.06  51.26  18.20 4     MSIE     MSIE 9.0   2.81  54.07  51.26 5  Firefox  Firefox 3.5   1.58  55.65  54.07 6  Firefox  Firefox 3.6  13.12  68.77  55.65 7  Firefox  Firefox 4.0   5.43  74.20  68.77 8   Chrome  Chrome 10.0   9.91  84.11  74.20 9   Safari   Safari 4.0   1.42  85.53  84.11 10  Safari   Safari 5.0   4.55  90.08  85.53 11   Opera   Opera 11.x   1.65  91.73  90.08 

So far, I have plotted the individual components (i.e. the donut chart of the versions, and the pie chart of the browsers) like so:

ggplot(browsers) + geom_rect(aes(fill=version, ymax=ymax, ymin=ymin, xmax=4, xmin=3)) + coord_polar(theta="y") + xlim(c(0, 4)) 

enter image description here

ggplot(browsers) + geom_bar(aes(x = factor(1), fill = browser),width = 1) + coord_polar(theta="y") 

enter image description here

The problem is, how do I combine the two to look like the topmost image? I have tried many ways, such as:

ggplot(browsers) + geom_rect(aes(fill=version, ymax=ymax, ymin=ymin, xmax=4, xmin=3)) +         geom_bar(aes(x = factor(1), fill = browser),width = 1) + coord_polar(theta="y") + xlim(c(0, 4))  

But all my results are either twisted or end with an error message.

like image 936
Tavi Avatar asked Nov 05 '14 01:11

Tavi


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1 Answers

Edit 2

My original answer is really dumb. Here is a much shorter version which does most of the work with a much simpler interface.

#' x      numeric vector for each slice #' group  vector identifying the group for each slice #' labels vector of labels for individual slices #' col    colors for each group #' radius radius for inner and outer pie (usually in [0,1])  donuts <- function(x, group = 1, labels = NA, col = NULL, radius = c(.7, 1)) {   group <- rep_len(group, length(x))   ug  <- unique(group)   tbl <- table(group)[order(ug)]    col <- if (is.null(col))     seq_along(ug) else rep_len(col, length(ug))   col.main <- Map(rep, col[seq_along(tbl)], tbl)   col.sub  <- lapply(col.main, function(x) {     al <- head(seq(0, 1, length.out = length(x) + 2L)[-1L], -1L)     Vectorize(adjustcolor)(x, alpha.f = al)   })    plot.new()    par(new = TRUE)   pie(x, border = NA, radius = radius[2L],       col = unlist(col.sub), labels = labels)    par(new = TRUE)   pie(x, border = NA, radius = radius[1L],       col = unlist(col.main), labels = NA) }  par(mfrow = c(1,2), mar = c(0,4,0,4)) with(browsers,      donuts(share, browser, sprintf('%s: %s%%', version, share),             col = c('cyan2','red','orange','green','dodgerblue2')) )  with(mtcars,      donuts(mpg, interaction(gear, cyl), rownames(mtcars)) ) 

enter image description here


Original post

You guys don't have givemedonutsorgivemedeath function? Base graphics are always the way to go for very detailed things like this. Couldn't think of an elegant way to plot the center pie labels, though.

givemedonutsorgivemedeath('~/desktop/donuts.pdf')  

Gives me

enter image description here

Note that in ?pie you see

Pie charts are a very bad way of displaying information. 

code:

browsers <- structure(list(browser = structure(c(3L, 3L, 3L, 3L, 2L, 2L,    2L, 1L, 5L, 5L, 4L), .Label = c("Chrome", "Firefox", "MSIE",    "Opera", "Safari"), class = "factor"), version = structure(c(5L,    6L, 7L, 8L, 2L, 3L, 4L, 1L, 10L, 11L, 9L), .Label = c("Chrome 10.0",    "Firefox 3.5", "Firefox 3.6", "Firefox 4.0", "MSIE 6.0", "MSIE 7.0",    "MSIE 8.0", "MSIE 9.0", "Opera 11.x", "Safari 4.0", "Safari 5.0"),    class = "factor"), share = c(10.85, 7.35, 33.06, 2.81, 1.58,    13.12, 5.43, 9.91, 1.42, 4.55, 1.65), ymax = c(10.85, 18.2, 51.26,    54.07, 55.65, 68.77, 74.2, 84.11, 85.53, 90.08, 91.73), ymin = c(0,    10.85, 18.2, 51.26, 54.07, 55.65, 68.77, 74.2, 84.11, 85.53,    90.08)), .Names = c("browser", "version", "share", "ymax", "ymin"),   row.names = c(NA, -11L), class = "data.frame")  browsers$total <- with(browsers, ave(share, browser, FUN = sum))  givemedonutsorgivemedeath <- function(file, width = 15, height = 11) {   ## house keeping    if (missing(file)) file <- getwd()   plot.new(); op <- par(no.readonly = TRUE); on.exit(par(op))    pdf(file, width = width, height = height, bg = 'snow')    ## useful values and colors to work with   ## each group will have a specific color   ## each subgroup will have a specific shade of that color   nr <- nrow(browsers)   width <- max(sqrt(browsers$share)) / 0.8    tbl <- with(browsers, table(browser)[order(unique(browser))])   cols <- c('cyan2','red','orange','green','dodgerblue2')   cols <- unlist(Map(rep, cols, tbl))    ## loop creates pie slices   plot.new()   par(omi = c(0.5,0.5,0.75,0.5), mai = c(0.1,0.1,0.1,0.1), las = 1)   for (i in 1:nr) {     par(new = TRUE)      ## create color/shades     rgb <- col2rgb(cols[i])     f0 <- rep(NA, nr)     f0[i] <- rgb(rgb[1], rgb[2], rgb[3], 190 / sequence(tbl)[i], maxColorValue = 255)      ## stick labels on the outermost section     lab <- with(browsers, sprintf('%s: %s', version, share))     if (with(browsers, share[i] == max(share))) {       lab0 <- lab     } else lab0 <- NA      ## plot the outside pie and shades of subgroups     pie(browsers$share, border = NA, radius = 5 / width, col = f0,          labels = lab0, cex = 1.8)      ## repeat above for the main groups     par(new = TRUE)     rgb <- col2rgb(cols[i])     f0[i] <- rgb(rgb[1], rgb[2], rgb[3], maxColorValue = 255)      pie(browsers$share, border = NA, radius = 4 / width, col = f0, labels = NA)   }    ## extra labels on graph    ## center labels, guess and check?   text(x = c(-.05, -.05, 0.15, .25, .3), y = c(.08, -.12, -.15, -.08, -.02),         labels = unique(browsers$browser), col = 'white', cex = 1.2)    mtext('Browser market share, April 2011', side = 3, line = -1, adj = 0,          cex = 3.5, outer = TRUE)   mtext('stackoverflow.com:::maryam', side = 3, line = -3.6, adj = 0,         cex = 1.75, outer = TRUE, font = 3)   mtext('/questions/26748069/ggplot2-pie-and-donut-chart-on-same-plot',         side = 1, line = 0, adj = 1.0, cex = 1.2, outer = TRUE, font = 3)   dev.off() }  givemedonutsorgivemedeath('~/desktop/donuts.pdf') 

Edit 1

width <- 5  tbl <- table(browsers$browser)[order(unique(browsers$browser))] col.main <- Map(rep, seq_along(tbl), tbl) col.sub  <- lapply(col.main, function(x)   Vectorize(adjustcolor)(x, alpha.f = seq_along(x) / length(x)))  plot.new()  par(new = TRUE) pie(browsers$share, border = NA, radius = 5 / width,     col = unlist(col.sub), labels = browsers$version)  par(new = TRUE) pie(browsers$share, border = NA, radius = 4 / width,     col = unlist(col.main), labels = NA) 
like image 88
rawr Avatar answered Sep 19 '22 01:09

rawr