I need to input a two strings, with the first one being any word and the second string being a part of the previous string and i need to output the number of times string number two occurs. So for instance:String 1 = CATSATONTHEMAT String 2 = AT. Output would be 3 because AT occurs three times in CATSATONTHEMAT. Here is my code:
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String word8 = sc.next();
String word9 = sc.next();
int occurences = word8.indexOf(word9);
System.out.println(occurences);
}
It outputs 1
when I use this code.
Interesting solution:
public static int countOccurrences(String main, String sub) {
return (main.length() - main.replace(sub, "").length()) / sub.length();
}
Basically what we're doing here is subtracting the length of main
from the length of the string resulting from deleting all instances of sub
in main
- we then divide this number by the length of sub
to determine how many occurrences of sub
were removed, giving us our answer.
So in the end you would have something like this:
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String word8 = sc.next();
String word9 = sc.next();
int occurrences = countOccurrences(word8, word9);
System.out.println(occurrences);
sc.close();
}
You could also try:
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String word8 = sc.nextLine();
String word9 = sc.nextLine();
int index = word8.indexOf(word9);
sc.close();
int occurrences = 0;
while (index != -1) {
occurrences++;
word8 = word8.substring(index + 1);
index = word8.indexOf(word9);
}
System.out.println("No of " + word9 + " in the input is : " + occurrences);
}
Why no one posts the most obvious and fast solution?
int occurrences(String str, String substr) {
int occurrences = 0;
int index = str.indexOf(substr);
while (index != -1) {
occurrences++;
index = str.indexOf(substr, index + 1);
}
return occurrences;
}
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